1. You have that:
- The homeowner<span> want the length of the swimming pool to be 4 feet longer than its width.</span>
- He wants to surround it with a concrete walkway 3 feet wide.
- He can only afford 300 square feet of concrete for the walkway.
2. Therefore, the tota area is:
At=L2xW2
L2 is the lenght of the walkway (L2=L1+3+3⇒L2=(W1+4+6)⇒L2=W1+10).
W2 is the width of the walkway (W1+3+3⇒W2=W1+6)
3. The area of the walkway is:
A2=At-A1
A2=300 ft²
4. Therefore, you have that the width of the swimming pool is:
A2=(W1+10)(W1+6)-(W1+4)(W1)
300=(W1²+6W1+10W1+60)-(W1²+4W1)
W1²+16W1+60-W1²-4W1-300=0
12W1-240=0
W1=240/12
W1=20 ft
5. And the length is:
L1=W1+4
L1=20+4
L1=24 ft
Answer:
3n−32=7n+28
n=-15
Step-by-step explanation:
Let's solve your equation step-by-step.
3n−32=7n+28
Step 1: Subtract 7n from both sides.
3n−32−7n=7n+28−7n
−4n−32=28
Step 2: Add 32 to both sides.
−4n−32+32=28+32
−4n=60
Step 3: Divide both sides by -4.
−4n/−4=60/−4
n=−15
No, because the 9 pounds would cost 22.5, and that is 5 cents more than he has
Area of a circle=πr²
r=radius=13 cm
area of a circle=π(13 cm)²=169π cm²≈530.93 cm²≈530.7 cm²
Answer: B.530.7 cm²
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