Answer:
can u send the full page most of the words are cut out
From A draw the altitude AH intersecting BC in H
Let's prove that triangle ABH is congruent to triangle ACH
The above 2 triangles are right triangles due to the altitude AH
Angle B= Angle C (given)
Angle AHB = Angle AHC =90° (since AH is the altitude)
Then angle BAH = CAH (both complementary to B & C respectively
And AH is a common side
Now Tri. ABH = Tri. ACH because ASA, hence AB=AC
Answer:
A)1/2
Step-by-step explanation:
Answer:
y = -2x - 1 ; slope = -2, y-intercept = (0, -1)
Step-by-step explanation:
to get the slope and y intercept, you need to put the equation into slope-intercept form: y = mx + b
the term mx is the slope of the line, and b is the y-intercept
to do this, you need to solve for y, so get y by itself by subtracting 8x from the left side
8x + 4y = -4
-8x. -8x
4y = -8x - 4
divide both sides by 4 to get y alone
4y/4 = y
-8x/4 = -2x
-4/4 = -1
y = -2x - 1 is the final equation
the slope of the line is -2 (also can be said as -2/1), and the line intercepts the y-axis at (0,-1)
10 + 8 + 7 = 25. So every fruit represents 4%. 8 oranges represent 32%. 10 apples represent 40%. and 7 pears represent 28%.
Hope this helped
