Answer:
0.5 < t < 2
Step-by-step explanation:
The function reaches its maximum height at ...
t = -b/(2a) = -16/(2(-16)) = 1/2 . . . . . . where a=-16, b=16, c=32 are the coefficients of f(t)
The function can be factored to find the zeros.
f(t) = -16(t^2 -1 -2) = -16(t -2)(t +1)
The factors are zero for ...
x = -1 and x = +2
The ball is falling from its maximum height during the period (0.5, 2), so that is a reasonable domain if you're only interested in the period when the ball is falling.
Answer: First option
Step-by-step explanation:
By definition, the horizontal shift depends on the value of <em>h </em>and the vertical shift depends on the value of <em>k</em><u>.</u>
indicates that the function if shifted to the right <em>h </em> units.
indicates that the function if shifted to the left <em>h </em> units.
indicates that the function if shifted down <em>k </em> units.
indicates that the function if shifted up <em>k </em> units.
Then:
If <em>h </em>is positive, the graph will shift to the right.
If <em>k </em>is negative, the graph will shift down.
As you can see in the graph, the function is shifted 4 units to the right and 2 units down. Therefore g(x) has the form:

Where:

Critical points is where the derivative (slope) is zero or does not exist. So to do this we have to find the derivative of our function:

So we apply chain rule:
=

Set our first derivative to zero and solve for x:
3(x^2 - 1) * 2x = 0
So we can see that (by plugging in) 0, -1 and 1 makes our solution true
So our critical value is x = 0, x = -1, x = 1