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Fed [463]
2 years ago
12

In your own words, explain

Mathematics
1 answer:
Nutka1998 [239]2 years ago
8 0

Answer:

a 2d is basically something that is flat, or like a graph. it doesnt have a volume.

a 3d is something that has a volume, it has sides and front and back.

2d ex; a graph on paper

3d ex; a square or rectangular box

Step-by-step explanation:

hope it helps

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I WILL GIVE A FREAKING BRAINLIEST!!!!!!!!!!!
UkoKoshka [18]

Answer:

  0.5 < t < 2

Step-by-step explanation:

The function reaches its maximum height at ...

  t = -b/(2a) = -16/(2(-16)) = 1/2 . . . . . . where a=-16, b=16, c=32 are the coefficients of f(t)

The function can be factored to find the zeros.

  f(t) = -16(t^2 -1 -2) = -16(t -2)(t +1)

The factors are zero for ...

  x = -1 and x = +2

The ball is falling from its maximum height during the period (0.5, 2), so that is a reasonable domain if you're only interested in the period when the ball is falling.

5 0
3 years ago
The parent function f(x) = x3 is translated to form g(x), as shown on the graph. The translated function can be written in the f
OLEGan [10]

Answer: First option

Step-by-step explanation:

By definition, the horizontal shift depends on the value of <em>h </em>and the vertical shift depends on the value of <em>k</em><u>.</u>

f(x)=(x-h)^3 indicates that the function if shifted to the right <em>h </em> units.

f(x)=(x+h)^3 indicates that the  function if shifted to the left <em>h </em> units.

f(x)=f(x)-k indicates that the  function if shifted  down <em>k </em> units.

f(x)=f(x)+k indicates that the  function if shifted up <em>k </em> units.

Then:

If <em>h </em>is positive, the graph will shift to the right.

If <em>k </em>is negative, the graph will shift down.

 As you can see in the graph, the function is shifted 4 units to the right and 2 units down. Therefore g(x) has the form:

 g(x)=(x-4)^3-2

Where:

h=4\\k=-2

7 0
2 years ago
FOR EASY BRAINLIEST!!! ANSWER WITH EXPLANATION:<br><br> 1.<br><br> 2.<br><br> 3.<br><br> 4.
spin [16.1K]

Answer:

1) 2

2) 5

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6 0
2 years ago
How do I find the critical points?
podryga [215]
Critical points is where the derivative (slope) is zero or does not exist. So to do this we have to find the derivative of our function:

\frac{d}{dx}(x^{2} - 1)^{3}

So we apply chain rule:

= 3(x^{2} - 1)^{2} * 2x

Set our first derivative to zero and solve for x:

3(x^2 - 1) * 2x = 0

So we can see that (by plugging in) 0, -1 and 1 makes our solution true

So our critical value is x = 0, x = -1, x = 1
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3 years ago
For breakfast, Mr hill bought a cup of coffee for 1.39 and a bagel for 1.85. How much change will he get for 5.00
notsponge [240]
Me hill will get 1.76 in change
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2 years ago
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