Answer:
Step-by-step explanation:
To find : Acceleration in first 15 min . Distance between two cities Average speed of journey
Solution:
Each horizontal block is 1/8 hr = 7.5 min
Each vertical block is 10 km/hr
Time Velocity km/hr
0 Min ( 0 hr) 0
15 Min (1/4 hr) 50
45 Min (3/4 hr) 50
60 MIn ( 1 hr) 100
90 Min ( 3/2 hr) 100
120 Min ( 2hr) 0
Acceleration in first 15 min (1/4 hr) = (50 - 0)/(1/4 - 0) = 50/(1/4)
= 200 km/h²
Distance between two cities
= (1/2)(0 + 50)(1/4 - 0) + 50 * (3/4 - 1/4) + (1/2)(50 + 100)(1 - 3/4) + 100 * (3/2 - 1) + (1/2)(100 + 0)(2 - 3/2)
= 25/4 + 25 + 75/4 + 50 + 25
= 125
Distance between two cities = 125 km
Average Speed of journey = 125/2 = 62.5 km/hr
Acceleration in first 15 min = 200 km/h²
Distance between two cities = 125 km
Average Speed of journey = 62.5 km/hr
Hope this helps..
Answer:1,627,190
Step-by-step explanation:
Answer:
Step-by-step explanation:
Isabell, can you see that the sides are 2x6 each? each half of the triangle will make a total rectangle of 2x6 or 12 square meters
there are 4 of those so 48 sq meters plus the base of 4x4 or 16 sq meters
48+16 = 64 square meters total
Answer:
x = 27
Step-by-step explanation:
vertical angles are congruent , then
5(x - 4) = 4x + 7 ← distribute parenthesis on left side
5x - 20 = 4x + 7 ( subtract 4x from both sides )
x - 20 = 7 ( add 20 to both sides )
x = 27
