Triangle Z W X is shown. Angle Z W X is a right angle. An altitude is drawn from point W to point Y on side Z X to form a right
1 answer:
Answer:
b = 9.1units
Step-by-step explanation:
Find the diagram attached
Using the similarity theorem of triangle
WX/XZ = WY/WX
Substitute;
b/a+5 = 6/b
b² = 6(a+5) ... 1
Also according to pythagoras theorem on triangle WYX;
b² = 6²+a²...2
Equate 1 and 2
6(a+5) = 6²+a²
6a+30 = 36 + a²
a²-6a+36-30 = 0
a²-6a+6 = 0
a = 6±√36+4(6)/2
a = 6±√60/2
a = 6±7.745/2
a = 13.745/2
a = 6.8725
Recall that
b² = 6²+a²
b² = 36+6.8725²
b² = 83.2313
b = 9.12units
b = 9.1units
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Answer:
Senn needs to give Ms. Lady 4.6 minutes head start
Senn needs to give Ms. Beetle 18.4 minutes head start
The equation for each bug are;
For Senn, the equation for the experiment is 5 × t₁ = 92 feet
For Ms. Lady, the equation for the experiment is 4 × (t₁ + 4.6) = 92 feet
For Ms. Beetle , the equation for the experiment is 4 × (t₁ + 18.4) = 92 feet
Please find attached the required graph and table of values
Step-by-step explanation:
The given parameters are;
The average crawling time of Ms. Lady = 4 feet per minute
The average crawling time of Ms. Beetle = 2.5 feet per minute
The average crawling time of Senn = 5 feet per minute
The distance to the rose bush = 92 feet
Therefore, we have;
The time, t, duration for Senn to arrive at the Rose bush is given by the following relation,
Time, t = Distance, d/(Speed, s)
Given that the speed of the bugs is equal to their average crawling time, we have
For Senn
Time, t = 92/(5 ft/Min) = 18.4 minutes
For, Ms. Lady
Time, t = 92/(4 ft/Min) = 23 minutes
For, Ms. Beetle
t = 92/(2.5 ft/Min) = 36.8 minutes
Therefore;
Senn needs to give Ms. Lady 23 - 18.4 = 4.6 minutes head start
Similarly, Senn needs to give Ms. Beetle 36.8 - 18.4 = 18.4 minutes head start
The equation for each bug are therefore;
For Senn, the equation for the experiment is given as follows ;
5 × t₁ = 92 feet
For Ms. Lady, the equation for the experiment is given as follows;
4 × (t₁ + 4.6) = 92 feet
For Ms. Beetle , the equation for the experiment is given as follows;
4 × (t₁ + 18.4) = 92 feet.
