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Fynjy0 [20]
3 years ago
12

Please answer asap thanks

Mathematics
1 answer:
andrezito [222]3 years ago
7 0

Answer:

V = 200 pi units ^3

Step-by-step explanation:

The volume of a cone is given by

V = 1/3 pi r^2 h

V = 1/3 pi ( 10 ^2) (6)

V = 1/3 pi (100) *6

V = 200 pi

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Nicole is half as old as Donald. The sum of their ages is 72. <br><br> How old is Nicole, in years?
bixtya [17]
Your gonna divide 72 by 2 so therefore you get 36
So that equals to Nicole’s age
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What percent of 18 is 4.5?
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8 0
3 years ago
Dan grew 22 pumpkins but tge rabbits ate 25 pumpkins.how many pumpkins does dan have left​
rodikova [14]

Answer:

0

Step-by-step explanation:

0 because he grew 22 but the rabbit ate 25 which does not make sense

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3 years ago
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A blouse that regularly sells for $28.50 is on sale for one-third off. what is the sale price of the dress?
egoroff_w [7]
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y=1/3x(2)
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7 0
3 years ago
A small business owner estimates his mean daily profit as $970 with a standard deviation of $129. His shop is open 102 days a ye
Katena32 [7]

Answer:

The probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we select appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sum of values of <em>X</em>, i.e ∑<em>X</em>, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{x}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

 \sigma_{x}=\sqrt{n}\sigma

The information provided is:

<em>μ</em> = $970

<em>σ</em> = $129

<em>n</em> = 102

Since the sample size is quite large, i.e. <em>n</em> = 102 > 30, the Central Limit Theorem can be used to approximate the distribution of the shopkeeper's annual profit.

Then,

\sum X\sim N(\mu_{x}=98940,\ \sigma_{x}=1302.84)

Compute the probability that the shopkeeper's annual profit will not exceed $100,000 as follows:

P (\sum X \leq  100,000) =P(\frac{\sum X-\mu_{x}}{\sigma_{x}}

                              =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

6 0
3 years ago
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