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3 years ago

In angle ABC, if measure angle A = 3x-7, measure angle B=9x-2, and measure angle C= x+7, Find the measure of each angle.

Mathematics

1 answer:

LekaFEV [45]3 years ago

3 0

Answer:

angle a = 28.5

angle b = 104.2

angle c= 18.8

Step-by-step explanation:

im not super sure if this is right, but i tried my best! have a good day! :3 <3

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hram777 [196]

Answer:

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y = 20

Step-by-step explanation:

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x = 12

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Evgen [1.6K]

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Pachacha [2.7K]

That would be 6 and 3/8

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Find the measure of CDE. The measure of CDE equals a certain # of degrees.

vredina [299]

2x-13+3x-8+2x-3+2x-7+3x-1+2x+11+2x+9= (7-2)×180

16x-12=(7-2)×180

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3 years ago

1-sinA+cosA / sinA+cosA-1 = 1+cosA/sinA

Art [367]

<u>Solution:</u>

$\dfrac{\left[\left(\sin ^{2} A+2 \times \sin A \times (1-\cos A)+(1-\cos A)^{2}\right]\right.}{\left[\left(1-\cos ^{2} A\right)-(1-\cos A)^{2}\right]}$

$\dfrac{\left[\left(1-\cos ^{2} A\right)+2 \times \sin A \times (1-\cos A)+(1-\cos A)^{2}\right]}{\left[(1-\cos A)(1+\cos A)-(1-\cos A)^{2}\right]}$

$\dfrac{(1-\cos A)[1+\cos A+2 \sin A+1-\cos A]}{[1-\cos A][1+\cos A-1+\cos A]}$

$\dfrac{[2+2 \sin A]}{[2 \times \cos A]}$

$\dfrac{2(1+\sin A)}{2 \times \cos A}$

$\dfrac{1+\cos A}{\sin A}$

<u>Hence Proved.</u>

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3 years ago