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Anit [1.1K]
3 years ago
5

The figure is symmetric about the x- and y-axis. what is the area of the figure below

Mathematics
1 answer:
kipiarov [429]3 years ago
3 0

Answer:

<em>126 units² </em>

Step-by-step explanation:

Draw 5 vertical lines BR, CQ, EO, GM, HL and we will have 4 trapezoids and 2 rectangles.

Trapezoid ABRS ≅ trapezoid IHLK

Trapezoid DEOP ≅ trapezoid FEON

Rectangle BCQR ≅ rectangle GHLM

Area of trapezoid is \frac{b_{1} +b_{2} }{2}h

Area of rectangle is lw  

The total area of the figure is: ( 2 × A_{ABRS} + 2 × A_{BCQR} + 2 × A_{DEOP} )

In trapezoid ABRS: b_{1} = 6, b_{2} = 8 and h = 3 ⇒

2 × A_{ABRS} = 2 × [3(6 + 8) ÷ 2] = <u><em>42 units²</em></u>

In rectangle BCQR: l = 6 and w = 3 ⇒

2 × A_{BCQR} = 2 × (6 × 3) = <u><em>36 units²</em></u>

In trapezoid DEOP: b_{1} = 6, b_{2} = 10 and h = 3 ⇒

2 × A_{DEOP} = 2 × [3(6 + 10) ÷ 2] = <u><em>48 units²</em></u>  

A_{total} = 42 + 36 + 48 = <em>126 units²</em>  

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