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frozen [14]
3 years ago
7

What does an "embedded video" mean

Computers and Technology
1 answer:
ipn [44]3 years ago
5 0
It’s when you are hosting the video at another location and simply linking to it
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(Java) Write a program that accepts a number of minutes and converts it both to hours and days. For example, 6000 minutes is 100
iogann1982 [59]
Import java.util.Scanner;
public class MinutesConversion {
private static Scanner inputDevice;
public static void main(String[] args) {
int minutes, hours;
float days; // float for decimal point

inputDevice = new Scanner(System.in);
System.out.println("Please enter minutes for conversion >> ");
minutes = inputDevice.nextInt();
hours = minutes / 60;
days = hours / 24.0f;


System.out.println(+ minutes + " minutes is " + hours + " hour(s) or" + days " days");
}
}
6 0
3 years ago
What is the magnitude of the largest positive value you can place in a bool? a char? an int? a float? a double??
Elena L [17]
The <span>magnitude of the largest positive value you can place in a bool, a char, an int, a float, a double are as follows:

</span><span>Int: 4 bytes Float: 4 double: 8 char: 1 boolean: 1
</span>
I hope my answer has come to your help. God bless and have a nice day ahead!
8 0
4 years ago
Only one person can receive the same email at the same time true or false
nasty-shy [4]

Answer:

false

Explanation:

5 0
3 years ago
Which of the following is applicable during a hostile act:
Elanso [62]
Your question has been up too long, a moderator may have to delete it.
we will contact moderators to find your question and remove it, and hopefully, they will refund the points, which is not up to me.
<span>thank you for using brainly.</span>
3 0
3 years ago
Write a program with 2 separate functions which compute the GCD (Greatest Common Denominator) and the LCM (Lowest Common Multipl
Maru [420]

Answer:

The program written in Python is as follows

def GCD(num1, num2):

    small = num1

    if num1 > num2:

         small = num2

    for i in range(1, small+1):

         if((num1 % i == 0) and (num2 % i == 0)):

              gcd = i

    print("The GCD is "+ str(gcd))

def LCM(num1,num2):

    big = num2  

    if num1 > num2:

         big = num1

    while(True):

         if((big % num1 == 0) and (big % num2 == 0)):

              lcm = big

              break

         big = big+1

     print("The LCM is "+ str(lcm))

 print("Enter two numbers: ")

num1 = int(input(": "))

num2 = int(input(": "))

GCD(num1, num2)

LCM(num1, num2)

Explanation:

This line defines the GCD function

def GCD(num1, num2):

This line initializes variable small to num1

    small = num1

This line checks if num2 is less than num1, if yes: num2 is assigned to variable small

<em>     if num1 > num2: </em>

<em>          small = num2 </em>

The following iteration determines the GCD of num1 and num2

<em>     for i in range(1, small+1): </em>

<em>          if((num1 % i == 0) and (num2 % i == 0)): </em>

<em>               gcd = i </em>

This line prints the GCD

    print("The GCD is "+ str(gcd))

   

This line defines the LCM function

def LCM(num1,num2):

This line initializes variable big to num2

    big = num2  

This line checks if num1 is greater than num2, if yes: num1 is assigned to variable big

<em>     if num1 > num2: </em>

<em>          big = num1 </em>

The following iteration continues while the LCM has not been gotten.

    while(True):

This if statement determines the LCM using modulo operator

<em>          if((big % num1 == 0) and (big % num2 == 0)): </em>

<em>               lcm = big </em>

<em>               break </em>

<em>          big = big+1 </em>

This line prints the LCM of the two numbers

     print("The LCM is "+ str(lcm))

The main starts here

This line prompts user for two numbers

print("Enter two numbers: ")

The next two lines get user inputs

num1 = int(input(": "))

num2 = int(input(": "))

This calls the GCD function

GCD(num1, num2)

This calls the LCM function

LCM(num1, num2)

<em></em>

<em>See attachment for more structured program</em>

Download txt
5 0
3 years ago
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