All categories

3 years ago

F(x) = -x^3-x Is this function odd?

Computers and Technology

2 answers:

Crank3 years ago

6 0

Answer:

yes it is odd beacuse 3 is a odd number

rosijanka [135]3 years ago

6 0

it's a odd function

Explanation:

a function is even if its F(-X) r F (x) and a function

is odd if its F(-X)= -F(x).

We have F(x)=x^3 - x and F (- x) = (-x)^3 - (-x)= -x^3

+ x = -(x^3 - x) = -F (x)

sorry if its confusing but it's an odd function ♡

You might be interested in

marshall27 [118]

Answer: c

Explanation:

5 0

3 years ago

Jeff’s father is installing a do-it-yourself security system at his house. He needs to get a device from his workshop that conve

Alenkasestr [34]

Answer:

Beeper

Explanation:

A buzzer pr beeper, as security device, converts electrical energy to sound energy.

3 0

4 years ago

A sinewave has a period (duration of one cycle) of 645 μs. What is the corresponding frequency of this sinewave, in kHz, express

irga5000 [103]

The corresponding frequency of this sinewave, in kHz, expressed to 3 significant figures is: 155 kHz.

Given the following data:

Period = 645 μs

Note: μs represents microseconds.

Conversion:

1 μs = $1$ × $10^{-6}$ seconds

645 μs = $645$ × $10^{-6}$ seconds

To find corresponding frequency of this sinewave, in kHz;

Mathematically, the frequency of a waveform is calculated by using the formula;

$Frequency = \frac{1}{Period}$

Substituting the value into the formula, we have;

$Frequency = \frac{1}{645\; * \;10^{-6}}$

Frequency = 1550.39 Hz

Next, we would convert the value of frequency in hertz (Hz) to Kilohertz (kHz);

Conversion:

1 hertz = 0.001 kilohertz

1550.3876 hertz = X kilohertz

Cross-multiplying, we have;

X = $0.001$ × $1550.39$

X = 155039 kHz

To 3 significant figures;

Frequency = 155 kHz

Find more information: brainly.com/question/23460034

5 0

3 years ago

Write an If...Then statement that assigns 0 to intX when intY is equal to 20

BigorU [14]

Answer:

wh,,what?

Explanation:

3 0

3 years ago

Read 2 more answers

A poker hand consists of 5 cards drawn at random without replacement from a 52 card deck. Using python and the cards data frame

PSYCHO15rus [73]

Answer:

# Python program to shuffle a deck of card

# importing modules

import itertools, random

# make a deck of cards

deck = list(itertools.product(range(1,14),['Spade','Heart','Diamond','Club']))

# shuffle the cards

random.shuffle(deck)

# draw five cards

print("You got:")

for i in range(5):

print(deck[i][0], "of", deck[i][1])

Output

You got:

5 of Heart

1 of Heart

8 of Spade

12 of Spade

4 of Spade

Explanation:

5 0

3 years ago