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erik [133]
2 years ago
15

You mix 1/ 3cup of blue paint for every 2/ 3cup of yellow paint to make green paint. You use 4 cups of yellow paint. How much bl

ue paint do you use?
Mathematics
1 answer:
Black_prince [1.1K]2 years ago
4 0

Answer:

You will use 2 cups of blue paint for 4 cups of yellow paint.

Step-by-step explanation:

Given that:

There is 1/3 cup of blue paint for every 2/3 cup of yellow paint

We will find unit rate in terms of yellow paint.

2/3 cups of yellow paint = 1/3 cup of blue paint

Multiplying both sides by 3/2

\frac{2}{3}*\frac{3}{2}=\frac{1}{3}*\frac{3}{2}\\1\ cup\ of\ yellow\ paint = \frac{1}{2}\ cup\ of\ blue\ paint

Now,

4 cups of yellow paint = 4*\frac{1}{2} cups of blue paint

4 cups of yellow paint = 2 cups of blue paint

Hence,

You will use 2 cups of blue paint for 4 cups of yellow paint.

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You must be dumb and have no friends

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3 years ago
The approximate volume of a sphere with a diameter of 10 centimeters is
Alexeev081 [22]

Answer: The volume is approximately 523.6 cm³.

Step-by-step explanation:

The formula for the volume of a sphere is V=4/3(3.14)r³

The radius is 5 cm, the you just have to multiply everything together.

5 0
3 years ago
How Do You Know How Many Places Are In Fifty Million Without Writing The Number In Standard Form
BartSMP [9]
Fifty million has 8 places
7 0
3 years ago
Help please!
Alina [70]

Step-by-step explanation:

Given

f(x) = 8x - 9

Then

For a.

f(3y - 1 ) = 8(3y - 1 ) - 9

= 24y - 8 - 9

= 24y - 17

Now for b.

f(x) = - 23

or, 8x - 9 = - 23

8x = - 23 + 9

8x = - 14

x = - 14 / 8

x = - 7 / 4

Hope it will help :)

7 0
2 years ago
Find the sum of a finite geometric sequence from n=1 to n=8, using the expression -2(3)^n-1
MissTica
\bf \qquad \qquad \textit{sum of a finite geometric sequence}
\\\\
S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}
\end{cases}
\\\\\\
\sum\limits_{n=1}^{8}~-2(3)^{n-1}~~
\begin{cases}
n=8\\
a_1=-2\\
r=3
\end{cases}\implies S_8=-2\left( \cfrac{1-3^8}{1-3} \right)
\\\\\\
S_8=\underline{-2}\left( \cfrac{1-6561}{\underline{-2}} \right)\implies s_8=1-6561\implies S_8=-6560
8 0
3 years ago
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