You want to find the closest ten thousand that there is to 639,121.
So a ten thousand is basically anything that ends with four or more zeros.
For example:
530000 would be a ten thousand because it has four zeros at the end.
So you can see what the closest ten thousands are to 639,121 would be.
They would be:
630,000 and 640,000
Since they both have four zeros at the end.
Now you can just tell that 639,121 is closer to 640,000 because the digit in the thousands place, 9, is closer to 10 than 0.
Hope this helped :)
X=3
y=5
You have to cancel out either the x values or the y values (I chose y). You multiply both equations by particular numbers so either the x values or y values can be equal to each other, as well as positive or negative to each other. I multiplied -7y by 4 and 4y by 7, and got -28y and 28y. I then canceled those out. The numbers you multiply by also affects the rest of the equations, so I ended up with 48x=4 and -35x=35. After that, you combine like terms, which results in 13x=39. You divide 13 by both sides and you end up with x=3. To find y, all you have to do is plug in the x value to one of the equations, then solve for y. I resulted in y=5.
Hope this helped ^_^
Answer:
He should cross multiply 90 and 60, and then divide by 100. The answer is 54.
Answer:
-7
Step-by-step explanation:
-9q = 63
q= 63/-9 = -7
Answer:
no
Step-by-step explanation:
To determine if (1, 6) is a solution, substitute x = 1, y = 6 into the left side of both equations and if the value obtained equals the right side then it is a solution.
10(1) - 6 = 10 - 6 = 4 ≠ - 6
- 10(1) + 5(6) = - 10 + 30 = 20 ≠ 30
Then (1, 6 ) is not a solution to the system
