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never [62]
3 years ago
9

PLZ HALP I WILL MARK BRAILYEST NO LINKS OR DOWNLOADS PLZZZZZZZZZZZZZ

Mathematics
1 answer:
stellarik [79]3 years ago
3 0

Answer:

D.

Step-by-step explanation:

Least value = 22 and greatest = 30

Arrange in order:

22 22 23 23 24 25 26 27 28 30

So the median is the mean of the middle 2:

= (24+25)/2 = 24.5.

Also Q1 = 23 and Q3 = 27

So the correct  plot is D.

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PLEASE PEOPLE, HELP ME!! Geometry
Oksanka [162]
I use the sin rule to find the area

A=(1/2)a*b*sin(∡ab)

1) A=(1/2)*(AB)*(BC)*sin(∡B)
sin(∡B)=[2*A]/[(AB)*(BC)]

we know that
A=5√3
BC=4
AB=5
then

sin(∡B)=[2*5√3]/[(5)*(4)]=10√3/20=√3/2
(∡B)=arc sin (√3/2)= 60°

 now i use the the Law of Cosines 

c2 = a2 + b2 − 2ab cos(C)

AC²=AB²+BC²-2AB*BC*cos (∡B)

AC²=5²+4²-2*(5)*(4)*cos (60)----------- > 25+16-40*(1/2)=21

AC=√21= 4.58 cms

the answer part 1) is 4.58 cms

2) we know that

a/sinA=b/sin B=c/sinC

and

∡K=α

∡M=β

ME=b

then

b/sin(α)=KE/sin(β)=KM/sin(180-(α+β))

KE=b*sin(β)/sin(α)

A=(1/2)*(ME)*(KE)*sin(180-(α+β))

sin(180-(α+β))=sin(α+β)

A=(1/2)*(b)*(b*sin(β)/sin(α))*sin(α+β)=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

KE/sin(β)=KM/sin(180-(α+β))

KM=(KE/sin(β))*sin(180-(α+β))--------- > KM=(KE/sin(β))*sin(α+β)

the answers part 2) are

side KE=b*sin(β)/sin(α)
side KM=(KE/sin(β))*sin(α+β)
Area A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

5 0
3 years ago
If f(x) = -1, solve for x.
weeeeeb [17]

Answer:

No solution.

Explanation:

The roots (zeros) are the x values where the graph intersects the x-axis. To find the roots (zeros), replace f(x) with 0 and solve for x.

3 0
3 years ago
Which of the set of ordered pairs contains the line<br> 1/3 x+y= 15.
Dima020 [189]

Answer: c

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Help plssssss!!!!!!!!!?????
Semenov [28]
Y=7x-10
Plz mark me Brainly
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5 0
3 years ago
Read 2 more answers
Help me pleaseee I need help
MAVERICK [17]
I think it is b because probability of 2 is 1/6 then probability of 4 is 1/6. If you times them together 1/6x1/6 it will equal 1/36 so b
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3 years ago
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