Answer:
10 terms
Step-by-step explanation:
equate the sum formula to 55 and solve for n
n(n + 1) = 55 ( multiply both sides by 2 to clear the fraction )
n(n + 1) = 110 ← distribute parenthesis on left side
n² + n = 110 ( subtract 110 from both sides )
n² + n - 110 = 0 ← in standard form
Consider the factors of the constant term (- 110) which sum to give the coefficient of the n- term (+ 1)
the factors are + 11 and - 10 , since
11 × - 10 = - 110 and 11 - 10 = + 1 , then
(n + 11)(n - 10) = 0 ← in factored form
equate each factor to zero and solve for n
n + 11 = 0 ⇒ n = - 11
n - 10 = 0 ⇒ n = 10
However, n > 0 , then n = 10
number of terms which sum to 55 is 10
Answer:
Given: circle
diameter = 10 cm => radius (R) = 5 cm
Find: measure of angle bounding sector = 11 π sq. cm.
Plan: determine what part of the circle’s total area equals the sector’s area.
Total Area of Circle A = π R^2 = π 5^2 = 25 π sq. cm.
Therefore: Sector Area = 11 π cm^2/25 π cm^2 = 11/25
Since the sector is 11/25 th of the circles area, the sector angle will measure 11/25 th of the circle’s circumference. They are proportional.
C = 2 π R = 2 π (5) = 10 π cm
Sector Arc = measure of sector angle = 11/25 (10 π) =
22π/5 radians
Answer: Sector Arc = 22π/5 Radians
The -1 affects the coefficient of the entire term.
Without the -1,
the term has a positive coefficient.
(3a)² = 9a²
However, with the -1,
the term has a negative coefficient.
-(3a)² = -9a²
Given the system of equations:
To solve it by substitution, follow the steps below.
Step 1: Solve one linear equation for x in terms of y.
Let's choose the second equation. To solve it for x, add 3y to each side of the equations.
Step 2: Substitute the expression found for x in the first equation.
Step 3: Isolate y in the equation found in step 2.
To do it, first, add 48 to both sides.
Then, divide both sides by 15.
Step 4: Substitute y by 5 in the relation found in step 1 to find x.
Answer:
x = -9
y = 5
or (-9, 5)
Also, you can graph the lines by choosing two points from each equation, according to the picture below.
