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2 years ago

Someone please help please and actually Answer

Mathematics

1 answer:

jarptica [38.1K]2 years ago

3 0

Rhombus I believe is correct

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A crew will arrive in one week and begin filming a city for a movie. The mayor is desperate to clean the city streets before fil

Reptile [31]

Step-by-step explanation:

1 week = 7 days of 24 hours each = 7×24 = 168 hours.

the first team can do 1/700 of the total work per hour.

the second team can do 1/600 if the total work per hour.

if they work together, then 1/700 + 1/600 of the total work can be done per hour.

to add these 2 fractions we need to bring them to the same denominator. and that would be 4200 (LCM of 700 and 600).

1/700 + 1/600 = 6/4200 + 7/4200 = 13/4200

so, together, they can do 13/4200 if the total job in 1 hour.

how many hours will they need together to finish the job ?

well, how often does 13 fit into 4200 (as 4200/4200 is the complete job) ?

4200 / 13 = 323.0769231... hours

so, it will still take a little bit over 323 hours to clean all the streets.

but there are only 168 hours until the film crew starts.

so, no, there is not enough time.

4 0

2 years ago

The quotient is 71 2/3 what is the divisor

zzz [600]

The answer to your question is 215

4 0

3 years ago

Read 2 more answers

Simplify to create an equivalent expression. 2(3r+7)−(2+r)

tamaranim1 [39]

2(3r+7)−(2+r)

Use distributive property:

6r + 14 - 2 - r

Simplify by combining like terms:

5r +12

7 0

3 years ago

How to do this question plz answer

Soloha48 [4]

Answer:

(⌐■-■)

Step-by-step explanation:

Add perimeter of a quarter circle with radius 7 cm.

Hope this helps....

Have a nice day!!!!

3 0

3 years ago

The number y of hits a new website receives each month can be modeled by y = 4070ekt, where t represents the number of months th

makvit [3.9K]

Answer:

k = 0.2645

Step-by-step explanation:

Given model:

y = 4070 $e^{kt}$

y = no. of hits website received = 9000 (in 3rd month)

t= no. of months website has been operational = 3

put in the above equation:

9000 = 4070 $e^{3k}$

$\frac{9000}{4070}$ = $e^{3k}$

$\frac{900}{407}$ = $e^{3k}$

Taking natural logarithm on both sides, we get:

$ln\frac{900}{407}$ = $ln(e^{3k})$

$ln\frac{900}{407}$ = 3k lne

lne=1

$ln \frac{900}{407}$ = 3k

or k = $\frac{1}{3}$ $ln\frac{900}{(407)}$

k = $\frac{1}{3}$ (0.7936)

k = 0.2645

7 0

3 years ago