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lapo4ka [179]
3 years ago
5

NO LINKS

Chemistry
1 answer:
Taya2010 [7]3 years ago
7 0
B because there is 2 gases in the air that we know of because of the text
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For IR radiation with û = 1,130 cm 1, v=__THz
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<u>Answer:</u> The frequency of the radiation is 33.9 THz

<u>Explanation:</u>

We are given:

Wave number of the radiation, \bar{\nu}=1130cm^{-1}

Wave number is defined as the number of wavelengths per unit length.

Mathematically,

\bar{\nu}=\frac{1}{\lambda}

where,

\bar{\nu} = wave number = 1130cm^{-1}

\lambda = wavelength of the radiation = ?

Putting values in above equation, we get:

1130cm^{-1}=\farc{1}{\lambda}\\\\\lambda=\frac{1}{1130cm^{-1}}=8.850\times 10^{-4}cm

Converting this into meters, we use the conversion factor:

1 m = 100 cm

So, 8.850\times 10^{-4}cm=8.850\times 10^{-4}\times 10^{-2}=8.850\times 10^{-6}m

  • The relation between frequency and wavelength is given as:

\nu=\frac{c}{\lambda}

where,

c = the speed of light = 3\times 10^8m/s

\nu = frequency of the radiation = ?

Putting values in above equation, we get:

\nu=\frac{3\times 10^8m/s}{8.850\times 10^{-4}m}

\nu=0.339\times 10^{14}Hz

Converting this into tera Hertz, we use the conversion factor:

1THz=1\times 10^{12}Hz

So, 0.339\times 10^{14}Hz\times \frac{1THz}{1\times 10^{12}Hz}=33.9THz

Hence, the frequency of the radiation is 33.9 THz

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Explanation:

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