84 m/s x 31.221 s = 2600 m
-rounded from 2622.564 m because 84 m/s has only two significant figures
Na₂CrO₄ + PbCl₂ → PbCrO₄ + 2 NaCl
<u>Explanation:</u>
In a double displacement reaction, the reactants which are involved in the reaction exchanging their ions thereby produces 2 new compounds. Here sodium chromate and lead chloride are undergoing double displacement reaction, the ions exchanges their position there by forming sodium chloride and lead chromate. So the double displacement reaction is given as,
Na₂CrO₄ + PbCl₂ → PbCrO₄ + 2 NaCl
The molar mass of CO2 can be calculated as follows;
CO2 — 12 + (16x2) = 12+ 32 = 44 g
Therefore molar mass of CO2 is 44 g/mol
In 44 g of CO2 there’s 1 mol of CO2
Then 1 g of CO2 there’s 1/44 mol of CO2
Therefore in 78.3 g of CO2 there’s — 1/44 x 78.3 =1.78 mol of CO2
The <u>Empirical formula</u> gives the smallest whole number ratio of moles of each element in a compound. therefore, multiple compounds may have it in common.
<h3>What is Empirical formula?</h3>
The most straightforward whole number ratio of atoms in a compound is its empirical formula. The empirical formula for sulfur monoxide, or SO, and disulfur dioxide, or S2O2, are both straightforward illustrations of this idea.
<h3>What is multiple compounds?</h3>
According to the law of multiple proportions, if two elements combine to form more than one compound, the ratio of the second element's mass to the fixed mass of the first element will always be a ratio of tiny whole numbers.
<h3>What is empirical formula used for?</h3>
Typically, the empirical formula is used to simply display the components of a molecule. When one needs to quickly identify the elements they are working with, this is helpful. When you want to know how many atoms of each element are present in the molecule, the molecular formula is most helpful.
To know more about empirical formula visit:
brainly.com/question/14044066
#SPJ4
MZn: 65 g/mol
mZnCl₂: 65g+35,5g×2 = 136 g/mol
.....................
Zn + 2HCl -----> ZnCl₂ + H₂
65g.......................136g............
65g Zn ---- 136g ZnCl₂
3,57g Zn ---- X
X = (3,57×136)/65
X = 7,47g ZnCl₂
