Answer:
See explanation and image attached
Explanation:
Now, we have chosen the alkene 1-propene in our example.
In the first reaction of 1-propene with HBr, the reaction proceeds by ionic mechanism leading to the formation of 2-bromo propane.
In the second reaction of 1-propene with the bromine molecule, the first step is the formation of the brominium cation which is a cyclic intermidiate followed by the addition of Br^- yielding the 1,2- dibromopropane product
Answer:
The given equation is Balanced.
Explanation:
AlBr₃ + 3K → 3KBr + Al
The balanced equation consist of equal number of atoms of elements in reactant and product side.
The given equation is balanced because one aluminium, three bromine and three potassium atoms are present on both side of equation.
I thinks it's C although I'm not 100% positive.
Answer:
Cr2O3
Explanation:
To find the empirical formula, which is the smallest whole number ratio of a compound, the following is done:
68.4% Cr = 68.4g of Chromium
31.6% O = 31.6g of Oxygen
Since, Cr = 52, O = 16, divide each mass by their respective atomic mass to convert to moles.
Cr = 68.4/52 = 1.315 mol
O = 31.6/16 = 1.975 mol
- Next, we divide each mole value by the smallest value (1.315mol)
Cr = 1.315/1.315 = 1
O = 1.975/1.315 = 1.50
The ratio or Cr to O is 1:1.5
We multiply this ratio by 2 to get the whole number ratio as follows:
2 × 1: 2 × 1.5
2:3
Hence, the empirical formula of Cr and oxygen is Cr2O3.