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vredina [299]
3 years ago
12

Consider the equation x^2-7x-8=0 and describe it's roots​

Mathematics
1 answer:
statuscvo [17]3 years ago
3 0

Answer:

there are two different, real roots.  

Step-by-step explanation:

The coefficients of this quadratic are {1, -7, -8}.  Let's find the discriminant, b^2 - 4ac.  In this case a = 1, b = -7 and c = -8 and so the discriminant value is

(-7)^2 - 4(1)(-8), or 49 + 32, or 81.

Because the discriminant is positive, we know immediately that there are two different, real roots.  

We are not asked to find the roots, but let's do it anyway:

      -(-7) ± √81

x = ------------------ => x = 8 and x = -2 (which are real and different from

              2                                           one another).

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Sergio039 [100]
It is 2.7737120471374
7 0
3 years ago
10. 12. 17<br>-- + -- + --<br>4. 6. 12​
SOVA2 [1]

Answer:

Step-by-step explanation:

I take it that what you mean is

10/4 + 12/6 + 17/12

Change all the questions so that their denominators are 12

10*3 / 4*3 + 12*2 / 6*2 + 17/12

30 / 12 + 24/12 + 17/12

(30 + 24 + 17)/12

71 / 12

5 11/12

5.917

7 0
3 years ago
What value in Vertex Form moves the graph up?
Leno4ka [110]
Changing from negative to positive
6 0
3 years ago
Nnnnnnnnnnnnnnnnnneeeeeed
amm1812

Answer: x 3

Step-by-step explanation:

x3 because you want the remove the fraction and make it a whole number. So x=45 would be the answer but x 3 is the operation.

4 0
4 years ago
Add. write your answer in simplest form.<br> -4 _/135 + 7 _/15
Zarrin [17]

\huge\quad\qquad\underline{{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  - 4 \sqrt{135} + 7 \sqrt{15}

\qquad \tt \dashrightarrow \: - 4 \sqrt{5 \times3 \times 3 \times 3}  + 7 \sqrt{15}

\qquad \tt \dashrightarrow \:( - 4 \times 3) \sqrt{5 \times 3}  + 7 \sqrt{15}

\qquad \tt \dashrightarrow \: - 12 \sqrt{15 }  + 7 \sqrt{15}

\qquad \tt \dashrightarrow \: - 5 \sqrt{15}

7 0
3 years ago
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