I’m not the best at graphs but i did take algebra, i think it’s graph number 2. also i’m sorry if it’s wrong:(
Answer:
Step-by-step explanation:
Given
slope =6/5
point =(5, -4)
So
the equation of the line =
(y-y1)=m(x-x1)
Where X1=5,y1=-4,m=6/5
Put the values
(Y+4)=6/5(x-5)
5(Y+4)=6(x-5)
5y+20=6x-30
5y-6x=-30-20
-6x+5y=-50
6x-5y=50.
So the equation of the line is 6x-5y=50.
Let Q1 and Q2 be the quotients from dividing 32 and 58 respectively.Then 32 Q1 + 30 = 58 Q2 + 4432 Q1 = 58 Q2 + 1416 Q1 = 29 Q2 + 716 Q1 = (16 + 13)Q2 + 716 Q1 = 16 Q2 + 13 Q2 + 716(Q1 - Q2) = 13 Q2 + 7Because Q1 and Q2 are integers, we have to find Q2 whereby 13Q2 + 7 is divisible by 16.After some try-and-error, we get Q2 = 13. That is 13*13 + 7 = 176Therefore, Q1 - Q2 = 11 --> Q1 - 13 = 11 --> Q1 = 2432*24 + 30 = 58*13 + 44 = 798.I am 798
I believe midpoint would be always. If someone else answers can I have brainliest? It will give you points back