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KonstantinChe [14]
3 years ago
11

Write the definition of a class Clock. The class has three instance variables: One of type int called hours, another of type boo

lean called isTicking, and the last one of type Integer called diff. You should also write a constructor that takes three parameters -- an int, a boolean, and another int. The constructor should set the instance variables to the values provided.
Mathematics
1 answer:
Vikki [24]3 years ago
6 0

Step-by-step explanation:

The definition of class as per given information is written below;

public class Clock

{

private int hours;

private boolean isTicking;

private Integer diff;

}

The constructor that takes the three variables and then set the values to the instance variables is;

public Clock (int hours, boolean isTicking, int diff)

{

this.hours = hours;

this.isTicking = isTicking;

this.diff = new Integer (diff);

}

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Can anybody help me???​
Tasya [4]

#10

\\ \rm\longmapsto 0

#11

  • Last three i.e Option B,C,D

#13

It started from negative ends at positive hence

\\ \rm\longmapsto y=-|x|+2

#14

  • (-3,-10)

\\ \rm\longmapsto 2(-3)-(-10)=4

\\ \rm\longmapsto -6+10=4

  • Proved

#15

  • (1,1)

\\ \rm\longmapsto 1=(1-2)^2=(-1)^2=1

#16

  • (2,-4)

\\ \rm\longmapsto -2-2(-4)>3

\\ \rm\longmapsto -2+8>3

\\ \rm\longmapsto 6>3

5 0
3 years ago
What's pi to as many decimal places?
Reil [10]
2 decimal places for regular . 3.14
4 0
3 years ago
A car travels 270 miles in 4.5 hours. What is the rate in miles per hour? D=R*T
kramer

Answer:60

Step-by-step explanation:you divide 270 by 4.5.

8 0
3 years ago
Line l is tangent to the graph of y= x - x²/500 at point Q & it crosses the y-axis at (0, 20)
insens350 [35]
A. Equation of line l: y = mx + 20 where m = y' = 1- (1/250)x 

At the point Q, The equation of the line equals the equation of the parabola. 

So (1-x/250)x + 20 = x - x^2/500 

20 = x^2/250 - x^2/500 = x^2/500 
x = sqrt(20*500) = 100ft 

B. m = 1 - 100/250 = 3/5. 

<span>Equation of line L is y = 3/5x + 20 
</span>
C)  If a spotlight is located at the x intercept of line L (-33 1/3,0), its light will go only above line L past the point where line L is tangent to the hill at (100,80) because the hill blocks the light below the tangent line. 

<span>The highest point on the equation of y = x - x²/500 is at (250,125), so a tree 50 feet tall at that location would reach up to (250,175). The tangent line goes through (250,170), so the top 5 feet of the tree would be above the tangent line, in the glow of the spotlight. 
</span>
--------------------------

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
8 0
3 years ago
For the expression StartFraction 15 x cubed + 25 x squared + 5 x + 2 Over (5 x squared + 1) squared EndFraction, which sum repre
Ilya [14]

Answer:

StartFraction 15 x cubed + 25 x squared + 5 x + 2 Over (5 x squared + 1) squared EndFraction, can be written in mathematical form as

Let y = \frac{15 x^3 + 25x^2 +5x+2}{({5x^2+1})^2}

on  expanding {({5x^2+1})^2 = 25x^4 +1 + 10x^2

⇒ y = \frac{15 x^3 + 25x^2 +5x+2}{25x^4 +1 + 10x^2}  

there correct form of partial fraction is \frac{15 x^3 + 25x^2 +5x+2}{25x^4 +1 + 10x^2}  

3 0
3 years ago
Read 2 more answers
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