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The perimeter of a rectangle:P = 2 L + 2 W
L ( length ) = 5.50 mW ( width ) = 12.0 mP = 2 * 5.50 + 2 * 12.0 = 11 + 24 = 35 mThe area of a rectangle:A = L x W
A = 5.50 * 12.0 = 66 m²Answer: 35, 66
Suppose the length of the triangle is x, if the perimeter of the rectangle is 100 ft, the width of the rectangle will be (50-x) ft.
Area of rectangle will be:
A=length*width
A=x(50-x)
A=50x-x^2
at maximum area, dA/dx=0
thus
dA/dx=50-2x=0
solving for x we get
2x=50
x=25
thus for maximum area length=25 ft
the size of the width will be
50-x=50-25=25 ft
thus the maximum area will be:
25*25=625 sq. feet
Answer:
Step-by-step explanation:
Since this is a right triangle, we can use the Pythagorean Theorem to solve for the sides.
where <em>a</em> and<em> b</em> are the legs and <em>c</em> is the hypotenuse. In this triangle, we know the legs are 9 centimeters and 11 centimeters, or:
Substitute these values into the formula.
Solve the exponents.
- (9 cm)²= 9 cm*9 cm=81 cm²
- (11 cm)²= 11 cm*11 cm= 121 cm²
Add the values on the left side.
Since we are solving for c, we must isolate the variable. It is being squared and the inverse of a square is the square root. Take the square root of both sides.
We are told to round to the nearest tenth.
The 1 in the hundredth place tells us to leave the 2 in the tenth place.
The hypotenuse is equal to <u>14.2 centimeters.</u>