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3 years ago

Easy math question need fast

Mathematics

1 answer:

ohaa [14]3 years ago

3 0

Answer:

∠BOC = 100°

Step-by-step explanation:

Given that,

∠BOC = 25x

and

∠COD = 20x

We need to find the measure of ∠BOC.

BOD is a straight line. Here, linear pair will form. So,

∠BOC+∠COD=180

25x+20x=180

45x=180

x=4

So,

∠BOC = 25(4)

= 100°

So, the measure of ∠BOC is equal to 100°.

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jonny [76]

Answer:

isosceles: 2 angles are the same and 2 sides are the same. Equilateral have all the same sides and angles. Saclene have all dfferent angles and sides.

11) isosceles

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2 years ago

Read 2 more answers

ΔEFG is located at E (0, 0), F (−7, 4), and G (0, 8). Which statement correctly classifies ΔEFG?

MariettaO [177]

Answer:

ΔEFG is an isosceles triangle.

Step-by-step explanation:

Given:

E (0, 0),

F (−7, 4),

G (0, 8)

ΔEFG

Solution:

Distance formula

Distance d = $\sqrt{(x_2-x_1)^2 +( y_2-y_1)^2$

Step 1: Finding the length of EF

By using distance formula,

$EF = \sqrt{(-7 - 0)^2 + (4-0)^2}$

$EF = \sqrt{(49) + (16)}$

$EF = \sqrt{(49) + (16)}\\EF = \sqrt{65}\\$

Step 2: Finding the length of FG

By using distance formula,

$FG = \sqrt{(0-(-7))^2+(8-4)^2}\\FG = \sqrt{(7)^2 +(4)^2}\\FG = \sqrt{49 +16}\\FG = \sqrt{65}$

Step 2: Finding the length of GE

$GE= \sqrt{(0-0)^2 + (0-8)^2}\\\\GE =\sqrt{(-8)^2}\\GE = \sqrt{64}\\GE = 8$

Thus we could see that the sides EF = FG

So it is a isosceles triangle.

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