3 years ago

Help plssssssssssssss???

Mathematics

1 answer:

KatRina [158]3 years ago

7 0

Answer:

Step-by-step explanation:

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Suppose that $g(x)=f^{-1}(x)$. If $g(-15)=0$, $g(0)=3$, $g(3)=9$ and $g(9)=20$, what is $f(f(9))$?

never [62]

Answer:

Step-by-step explanation:

$\text{If } g(x)=f^{-1}(x);$ and:$\\g(-15)=0,$ g(0)=3, g(3)=9, g(9)=20$

We are to determine the value of $f(f(9)).$

Now:

$g(0)=f^{-1}(0)=3\\g(3)=f^{-1}(3)=9$

From:

$g(3)=f^{-1}(3)=9\\f(9)=3$

From:

$g(0)=f^{-1}(0)=3\\f(3)=0$

Therefore:

$f(f(9))=f(3)=0$

8 0

3 years ago

Help please! any1 know this

ra1l [238]

Answer:

C, 3

Step-by-step explanation:

By creating a best line of fit you can get the sets of points (16,50) and (12,40)

Using these to find the slope we can get $\frac{40-50}{12-16} =\frac{-10}{-4}$

-10/-4 is 2.5 The best approximation would be C, because if you round it up to the nearest number you would get 3.

3 0

3 years ago

This , i don't know how to do this , I don't know how to find a, would you help me ?

scZoUnD [109]

To find a you need to do Sin(44) x 7 / sin(96)

That equals about 4.89

6 0

3 years ago

The points (0, −6) and (−10, 4) lie on the graph of a linear function.

Montano1993 [528]

-10, -10 is the answer

3 0

3 years ago

Read 2 more answers

14. Find the average of the 1000 whole numbers

steposvetlana [31]

Answer:

500.5

Step-by-step explanation:

The average of a set of numbers is the sum of the numbers divided by the number of numbers.

The sum of all whole number form 1 to n is n(n + 1)/2.

The sum of all whole numbers from 1 to 1000 is

1000(1000 + 1)/2 = 1000(1001)/2 = 500,500

The average is the sum of the numbers divided by the number of numbers.

average = 500,500/1000 = 500.5

5 0

3 years ago