The answer is D
16.55 divide by 2= 8.275
8.275+8.275+16.55+16.55=49.65
Let "a" and "s" represent the costs of advance and same-day tickets, respectively. Your problem statement gives you two relations.
.. a + s = 35 . . . . . the combined cost of one of each is 35
.. 15a +40s = 900 . . total paid for this combination of tickets was 900
There are many ways to solve these equations. You've probably been introduced to "substitution" and "elimination" (or "addition"). Using substitution for "a", we have
.. a = 35 -s
.. 15(35 -s) +40s = 900 . . substitute for "a"
.. 25s +525 = 900 . . . . . . . simplify
.. 25s = 375 . . . . . . . . . . . .subtract 525
.. s = 15 . . . . . . . . . . . . . . .divide by 25
Then
.. a = 35 -15 = 20
The price of an advance ticket was 20.
The price of a same-day ticket was 15.
Sana makatulong po sa inyo;)
Answer:
she messed up on step two because she has to subtract 10 from both sides
Step-by-step explanation:
step 1: -6(x+3)+10<-2
step2:-6(x+3)+10-10<-2-10
step3: -6(x+3)<-12
step4: (-6)(x+3)(-1)≥(-12)(-1)
step5:6(x+3)>12
step6:divide both sides by 6
step7:simplify and subtract 3 from both sides and then simplify again
