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3 years ago

I'll mark brainly if you do this

Mathematics

1 answer:

wariber [46]3 years ago

6 0

Answer:

look it up on Google

Step-by-step explanation:

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it costs $20 per hour to bowl and $3 for shoe rental. Write a verbal model and an algebraic expression to represent the cost for

katen-ka-za [31]

3 + 20x, where x= the number of hours bowled. A verbal diagram is where you say amount to pay per hour * number of hours + price of shoe rental = total cost.

5 0

3 years ago

I need the answer for 90 please its due tommorow!

babunello [35]

Jacqueline is incorrect.
To find how much trash you can clean in 4 days if you already know how much trash you can clean in one day, multiply 1 2/3 (how much you can clean in one day) by 4.
Another way to write 1 and 2/3 miles is 5/3 (converting a mixed number to a single fraction). Then, 5/3 x 4 = 20/3. (To multiply fractions, just multiply across, leaving 5 x 4 in the numerator and 4 x 1 in the denominator.)
Jacqueline said you would be able to clean 19/3 miles but you can actually clean 20/3.

4 0

3 years ago

Read 2 more answers

37. Verify Green's theorem in the plane for f (3x2- 8y2) dx + (4y - 6xy) dy, where C is the boundary of the

Nastasia [14]

I'll only look at (37) here, since

• (38) was addressed in 24438105

• (39) was addressed in 24434477

• (40) and (41) were both addressed in 24434541

In both parts, we're considering the line integral

$\displaystyle \int_C (3x^2-8y^2)\,\mathrm dx + (4y-6xy)\,\mathrm dy$

and I assume C has a positive orientation in both cases

(a) It looks like the region has the curves y = x and y = x ² as its boundary***, so that the interior of C is the set D given by

$D = \left\{(x,y) \mid 0\le x\le1 \text{ and }x^2\le y\le x\right\}$

• Compute the line integral directly by splitting up C into two component curves,

C₁ : x = t and y = t ² with 0 ≤ t ≤ 1

C₂ : x = 1 - t and y = 1 - t with 0 ≤ t ≤ 1

Then

$\displaystyle \int_C = \int_{C_1} + \int_{C_2} \\\\ = \int_0^1 \left((3t^2-8t^4)+(4t^2-6t^3)(2t))\right)\,\mathrm dt \\+ \int_0^1 \left((-5(1-t)^2)(-1)+(4(1-t)-6(1-t)^2)(-1)\right)\,\mathrm dt \\\\ = \int_0^1 (7-18t+14t^2+8t^3-20t^4)\,\mathrm dt = \boxed{\frac23}$

*** Obviously this interpretation is incorrect if the solution is supposed to be 3/2, so make the appropriate adjustment when you work this out for yourself.

• Compute the same integral using Green's theorem:

$\displaystyle \int_C (3x^2-8y^2)\,\mathrm dx + (4y-6xy)\,\mathrm dy = \iint_D \frac{\partial(4y-6xy)}{\partial x} - \frac{\partial(3x^2-8y^2)}{\partial y}\,\mathrm dx\,\mathrm dy \\\\ = \int_0^1\int_{x^2}^x 10y\,\mathrm dy\,\mathrm dx = \boxed{\frac23}$

(b) C is the boundary of the region

$D = \left\{(x,y) \mid 0\le x\le 1\text{ and }0\le y\le1-x\right\}$

• Compute the line integral directly, splitting up C into 3 components,

C₁ : x = t and y = 0 with 0 ≤ t ≤ 1

C₂ : x = 1 - t and y = t with 0 ≤ t ≤ 1

C₃ : x = 0 and y = 1 - t with 0 ≤ t ≤ 1

Then

$\displaystyle \int_C = \int_{C_1} + \int_{C_2} + \int_{C_3} \\\\ = \int_0^1 3t^2\,\mathrm dt + \int_0^1 (11t^2+4t-3)\,\mathrm dt + \int_0^1(4t-4)\,\mathrm dt \\\\ = \int_0^1 (14t^2+8t-7)\,\mathrm dt = \boxed{\frac53}$

• Using Green's theorem:

$\displaystyle \int_C (3x^2-8y^2)\,\mathrm dx + (4y-6xy)\,\mathrm dx = \int_0^1\int_0^{1-x}10y\,\mathrm dy\,\mathrm dx = \boxed{\frac53}$

4 0

3 years ago

The question is below thanks

Paha777 [63]

Answer:

FH ~ 10.02

Step-by-step explanation:

1. Approach

One should first find the circumference of the given circle. Then one should find how large the fraction of the circumference one is supposed to find is. Finally, one should multiply the fraction of the circumference one is supposed to find by the total circumference.

2. Circumference of the circle

The formula for circumference is;

$2r$ π

Substitute in the given values;

It is given that the radius is, hence

2 (7) π

14π

3. Find the fraction of the circumference one is supposed to find

It is given that the angles over the measure of the total degrees of angles in a circle are equal to the arc surrounding the angles of the circumference. Essentially;

$\frac{angles}{360}=\frac{arc}{circumference}$

Substitute in the given information and solve;

$\frac{82}{360}=\frac{arc}{14pi}$

arc = $\frac{41}{180}*14pi$

arc = $\frac{287}{90}*pi$

arc ~ 10.02

3 0

3 years ago

What is the solution of the equation f(x) = g(x) ?

dezoksy [38]

We are given the two functions $f(x) = x^{-\frac{1}{2} }$ and $g(x) = \sqrt{x} - \frac{3}{2}$ . Since the question is asking us for the value of x when f(x) is equal to g(x), all we need to do is equate the respective expressions together. This is what the result should be:
$x^{-\frac{1}{2}} = \sqrt{x} - \frac{3}{2}$
Now, just solve for x. If you want to save some time, you can use logic and then algebra. To do this, look at the square root. We cannot have an imaginary number, so we can rule out the first two options. Now, we are left with x = 2 and x = 4. When we plug in each x-value to the equation, only 4 works out with a result of 0.5 = 0.5. Therefore, the solution to f(x) = g(x) is D) x = 4. Hope this helps and have a great day!

4 0

3 years ago

I'll mark brainly if you do this​

I'll mark brainly if you do this