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GuDViN [60]
2 years ago
14

What is the equation of the line that passes through the point (2-,5) and a slope of -6???

Mathematics
1 answer:
zavuch27 [327]2 years ago
3 0

Answer:

y = -6x - 7

Step-by-step explanation:

We already know the slope so all we need to do is find th y-intercept. We can do this by using slope-intercept form and substituting the values we are given.

y = mx + b

5 = -6(-2) + b

5 = 12 + b

-7 = b

Put everything we know back into the formula.

y = -6x - 7

Best of luck!

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The edge represented by EA is the edge skewed to edge FG. Skew lines are non-intersecting lines in space. These lines are neither parallel nor they form right angles.
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3 years ago
What is the equation of a line passing through the point (-3,5) and has a slope of -6
IceJOKER [234]

Answer:

y = -6x — 13

Step-by-step explanation:

use y = mx + b equation and plug in what you know.

5 = -6(-3) + b —> solve for b

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ANSWER: y = -6x — 13

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3 years ago
What is the answer to 1/3-1/6
maxonik [38]
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5 0
2 years ago
Read 2 more answers
Sean and his chartered a fishing boat for the day Sean caught a blue marlin and an amberjack. The weight of the blue marlin way
Serjik [45]

Answer:

The weight of the blue marlin = b = 252 pounds

The weight of the amber jack = a = 12 pounds

Step-by-step explanation:

Sean and his chartered a fishing boat for the day Sean caught a blue marlin and an amberjack.

Let

The weight of the blue marlin = b

The weight of the amber jack = a

The weight of the blue marlin weigh 12 times as that of the amberjack.

b= 12a

The combined weight of both fish was 273 pounds.

= a + b = 273 pounds

b = 12a

Hence

a + 12a = 273 pounds

13a = 273 pounds

a = 273 pounds/13

a = 21 pounds

b = 12a

b = 12 × 21 pounds

= 252 pounds

Hence:

The weight of the blue marlin = b = 252 pounds

The weight of the amber jack = a = 12 pounds

4 0
2 years ago
What is the length?​
xxMikexx [17]

Answer:

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the line in the middle represents 1/2 because 5/10 is equal to 1/2

7 0
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