Answer:
A = 1100cm^2
Step by step Explanation:
given the dimensions of width and length of the picture are x+20 by 2x-10 and the frame is a constant 5 cm wider from the edge of the picture to the frame, than the area of the frame is defined as (x+30)(2x)-(x+20)(2x-10) = 30x+200.
If the width is equal to the length which I assume is true if the width is constant.
than x+30=2x, which means x = 30.
if this is true than 30(30)+200 = 1100cm^2
Which point could be removed in order to make the relation a function? {(0, 2), (3, 8), (–4, –2), (3, –6), (–1, 8), (8, 3)} Whic
myrzilka [38]
(3,-6) because you can't have two of the same x's in a function
Area of ∆ = 1/2 times its base × height
=1/2 × 4 × 5 UNIT²
=10 unit²
Area of semicircle = πr²/2
= (3.14)(4)²/2
=25.12 unit²
Therefore area of figure= 10+25.12 unit² = 35.12 unit²
Hope it helps!
Answer is A
Once you add 29 to negative 34 you will get negative 5 and then divide 5 and you will end up with negative 1 always flip the sign when dealing with a negative
D there answer is D kdkdkdbdhsbdejsiw
