SELECT ALL MODELS I WILL GIVE BRAINLIEST 6TH GRADE MATH

A caterpillar eats 1400\%1400%1400, percent of its birth mass in one day. The caterpillar's birth mass is mmm grams.

makvit [3.9K]

Answer:

I d k

Step-by-step explanation:

6 0

2 years ago

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A carpenter wants to make sure that the corner of a triangular frame he is building is a right angle. If he measures two sides o

Mama L [17]

13 feet
Pythagorus is used
25 + 144 = 169
169 is 13 to the second power etc

6 0

1 year ago

Clarinex is a drug used to treat asthma. In clinical tests of this drug, 1655 patients were treated with 5- mg doses of Clarinex

bagirrra123 [75]

Answer:

$z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363$

$p_v =P(z>3.363)=0.00039$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

Step-by-step explanation:

Data given and notation

n=1655 represent the random sample taken

$\hat p=0.021$ estimated proportion of interest

$p_o=0.012$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that true proportions is higher than 0.012.:

Null hypothesis: $p \leq 0.012$

Alternative hypothesis: $p > 0.012$

When we conduct a proportion test we need to use the z statisitic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>3.363)=0.00039$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

3 0

3 years ago

What is 8/6 in it simplest form

Alexxx [7]

Answer:

1.3 repeating

Step-by-step explanation:

8 0

2 years ago

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A line passes through the point (6, -8) and has a slope of -3/2

DENIUS [597]

Use y=mx + b, which is slope intercept form

b = y intercept(when x=0)
m = slope

You need to find the y intercept. Use your coordinates and substitute it in the slope intercept equation.

we use (6, -8)

y = mx + b

Then, -8 = -3/2(6) + b

-8 = -9 + b
1 = b

Thus,

y = -3/2x + 1

8 0

2 years ago