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kirza4 [7]
2 years ago
15

Kinsey purchased a bushel of large apples that weigh about 48 pounds.the bushel contains 96 apples what is the weight of one app

le
Mathematics
2 answers:
Elenna [48]2 years ago
6 0
Each with half a pound.
zhannawk [14.2K]2 years ago
6 0

Answer:

o8uhdoularsdjgv

Step-by-step explanation:

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Which value is included in the solution set for the inequality graphed one the number line?
Soloha48 [4]

<em>We can also graph inequalities on the number line. The following graph represents the inequality x≤2 . The dark line represents all the numbers that satisfy x≤2 . If we pick any number on the dark line and plug it in for x, the inequality will be true.</em>

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2 years ago
Round your answer to the nearest hundredth.
Karolina [17]

Answer:

tam 20 = 4 / x

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1 year ago
Simplify: 7(b-a)-7(b+a)
Natali [406]
Answer:
-14a

Explanation:
We are given 7(b - a) - 7(b + a).

We can distribute the 7’s to get:
7b - 7a - 7b - 7a

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5 0
2 years ago
Read 2 more answers
Jake rented a kayak at $26 for 3 hours. If he rents the same kayak for 5 hours, he has to pay a tota rent of $42. Write an equat
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Y=8x because 42-26 is 16 and divide that by the difference between the hours to get how much you pay per hour
5 0
2 years ago
(HELP MEH) Why is √​5​​ irrational?
xxTIMURxx [149]

Answer:

  D.)  because it cannot be expressed as a ratio of integers

Step-by-step explanation:

The root of any integer that is not a perfect square is irrational. 5 is not a perfect square, so is irrational—it cannot be expressed as the ratio of integers.

__

<em>Proof</em>

Suppose √5 = p/q, where p and q are mutually prime. Then p² = 5q².

If p is even, then q² must be even. We know that √2 is irrational, so the only way for q² to be even is for q to be even—contradicting our requirement on p and q.

If p is odd, then both p² and q² will be odd. We can say p = 2n+1, and q = 2m+1, so we have ...

  p² = 5q²

  (2n+1)² = 5(2m+1)²

  4n² +4n +1 = 20m² +20m +5

  4n² +4n = 4(4m² +4m +1)

  n(n+1) = (2m+1)²

The expression on the left will be even for any integer n; the expression on the right will be odd for any integer m. This equation cannot be satisfied for any integers m and n, so contradicting our assumption √5 = p/q.

We have shown using "proof by contradiction" that √5 cannot be the ratio of integers.

4 0
3 years ago
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