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muminat
3 years ago
13

The average human heart beats 75 times every minute. The average horse has a heartbeat of 40 times every minute. How many times

does a human heart beat in an hour? Which answer choice correctly identifies the extraneous information in this word problem?
Mathematics
1 answer:
Effectus [21]3 years ago
6 0

Answer:

4500

Step-by-step explanation:

multiply the amount of times the heart beats every minute and multiply it by how many minutes which is 60 so 75 times 60 is 4500

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A scale model of a rectangular patio is 6 feet long a 3 feet wide. The actual patio is 15 feet long. What Is the area of the act
valentina_108 [34]

Answer:

112.5 square feet

Step-by-step explanation:

The scale model is 6 x 3 and the actual patio is 15 x W

By the definition of a scale model,

15/6 = W/3

15 = 2W                       multiply both sides by 6

15/2 = W                      divide both sides by 2

Area of the patio  = length * width

Area = 15 feet * 15/2 feet = 225/2 square feet = 112.5 square feet

3 0
4 years ago
1. Opens down, with a stretch of 2, and has zeros at 3 and -2.
Artemon [7]

Answer:

f(x)= -2(x^2-x-6)

Step-by-step

The original formula is f(x)=a(x-h)+k

1) Plug the negative 2 in for a

2) multiply (x-3)(x+2)

3) plug your answer in for 2 in for the parentheses

6 0
4 years ago
What is the domain and range?
Alexxandr [17]
Domain: (2,3]
Range: (5,-2]
8 0
4 years ago
Which number, when substituted for x, makes the equation 4x+8=164x+8=16 true?
ra1l [238]
X = 2

4x + 8 = 16
      -8     -8
----------------
4x= 8
--     --
4     4
------------
x=2
7 0
3 years ago
Read 2 more answers
The vector v has initial point P(1, 0) and terminal point Q that is on the y-axis and above the initial point. Find the coordina
zloy xaker [14]

Answer:

The terminal point is Q(0,4)

Step-by-step explanation:

We are given the following in the question:

Initial point of vector, P(1,0)

The terminal point Q lies on the y-axis, thus Q have coordinates of the form:

Q(0,y)

The magnitude of the vector is \sqrt{65}

Magnitude is given by:

v = \sqrt{(x_2-x_2)^2+(y_2-y_1)^2}\\\sqrt{65}=\sqrt{(0-1)^2+(y-0)^2}\\\sqrt{65}=\sqrt{1+y^2}\\65 = 1+y^2\\y^2 = 64\\y = \pm 8

But since the terminal point is above the initial point, thus,

y > 0\\\Rightarrow y = 4

Thus, the terminal point is Q(0,4)

4 0
3 years ago
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