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SpyIntel [72]
3 years ago
7

16. In a group of 6 boys and 4 girls, four

Mathematics
1 answer:
lys-0071 [83]3 years ago
4 0

Answer:

209 different ways.

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How do you add mixed fractions?
ycow [4]
If u have 4\3 and 4\5 u add 4+4=8 and then do 5+3=8 and now you have 8\8 and that is how to add ixed fractions
3 0
3 years ago
Find the mean median mode and range for the following data 77 60 59 70 89 95
Advocard [28]

Answer:

Mean = 75

Median = 73.5

Mode = 95

Range = 36

Step-by-step explanation:

Given:

  • 77,60,59,70,89,95

Sort:

  • 59,60,70,77,89,95

To find:

  • Mean
  • Median
  • Mode
  • Range

Mean:

\displaystyle \large{\dfrac{1}{n}\sum_{i =1}^n x_i = \dfrac{x_1+x_2+x_3+...+x_n}{n}}

Sum of all data divides by amount.

\displaystyle \large{\dfrac{59+60+70+77+89+95}{6}=\dfrac{450}{6}}\\\\\displaystyle \large{\therefore mean=75}

Therefore, mean = 75

Median:

If it’s exact middle then that’s the median. However, if two data or values happen to be in <em>middle</em>:

\displaystyle \large{\dfrac{x_1+x_2}{2}}

From 59,60,70,77,89,95, since 70 and 77 are in middle:

\displaystyle \large{\dfrac{70+77}{2} = \dfrac{147}{2}}\\\displaystyle \large{\therefore median = 73.5}

Therefore, median = 73.5

Mode:

The highest value or/and the highest amount of data. Mode can have more than one.

From sorted data, there are no repetitive data nor same data. Consider the highest value:

Therefore, mode = 95

Range:

\displaystyle \large{x_{max}-x_{min}} or highest value - lowest value

Thus:

\displaystyle \large{95-59 = 36}

Therefore, range = 36

7 0
2 years ago
(x+5)(y+10) <br><br> what is the answer to this equation?
netineya [11]
(x + 5)(y + 10)
x(y + 10) + 5(y + 10)
x(y) + x(10) + 5(y) + 5(10)
xy + 10x + 5y + 50
7 0
3 years ago
How do historians define the term "causation​
Naily [24]

Your answer would be the relationship between two events in which one leads directly to the other occurring

5 0
3 years ago
2x^2 / x^2 - y^2 - x^2 / xy - y ^ 2​
Juliette [100K]

Answer:

2 - 2y^2 - x/y

Step-by-step explanation:

2x^2/x^2 = 2

and

x^2/xy = x/y

therefore

2x^2/x^2 - y^2 - x^2/xy - y^2

= 2 - y^2 - x/y - y^2

= 2 - y^2 - y^2 - x/y

= 2 - 2y^2 - x/y

6 0
3 years ago
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