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VARVARA [1.3K]
3 years ago
12

Jeremiah ate dinner at 6:17 pm . Before eating, it took him: - 25 minutes to cook dinner - 12 minutes to drive home from the gro

cery store - 36 minutes to the grocery shop. What time does Jeremiah arrive at the grocery store? Group of answer choices
Mathematics
1 answer:
tino4ka555 [31]3 years ago
6 0

Answer:

5:04 pm

Step-by-step explanation:

The computation of the time does Jeremiah arrive at the grocery store is shown below:

She ate dinner at 6:17 pm

She took 25 minutes for cooking

She took 12 minutes to drive home from grocery store

And, the 36 minutes to the grocery store

So, the time at which she arrive is

= 6.17pm - 25 minutes - 12 minutes - 36 minutes

= 6.17pm - 73 minutes

= 5:04 pm

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Answer:

P'(-6,-4)

Step-by-step explanation:

By translating the point under the translation, to put it into a simpler form, it says to move the point 4 units to the left and 6 units down. Using this, the point will move to P'(-6,-4)

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Steven and Bob both have a Pokemon card collection. The number of Pokemon cards in Steven's collection can be represented by x.
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Step-by-step explanation:

The number of Pokemon cards in Steven's collection = x

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A coffee machine can be adjusted to deliver any fixed number of ounces of coffee. if the machine has a standard deviation in del
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The mean will be calculates as follows; from the formula of z-score we shall have:
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3 years ago
The number of days (d) is equal
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A food processor packages orange juice in small jars. The weights of the filled jars are approximately normally distributed with
Ratling [72]

Answer:

P(X>10.983)=P(\frac{X-\mu}{\sigma}>\frac{10.983-\mu}{\sigma})=P(Z>\frac{10.983-10.5}{0.3})=P(z>1.61)

And we can find this probability using the complement rule and with excel or the normal standard table:

P(z>1.61)=1-P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(10.5,0.3)  

Where \mu=10.5 and \sigma=0.3

We are interested on this probability

P(X>10.983)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>10.983)=P(\frac{X-\mu}{\sigma}>\frac{10.983-\mu}{\sigma})=P(Z>\frac{10.983-10.5}{0.3})=P(z>1.61)

And we can find this probability using the complement rule and with excel or the normal standard table:

P(z>1.61)=1-P(z

8 0
3 years ago
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