2 hours she earns €16
3 hours she earns €24
Answer:
Profit for 100 burritos: $550
Cost to make one burrito: $2.50
Step-by-step explanation:
If a restaurant sells burritos for $8, that's a positive 8 dollars they earned. Then, we need to find what the cost was to make the burrito. If the meat is 1.50 and the cost for all the other ingredients is 1 dollar, then they lose 2.50 for every 8 dollars they make (for each burrito). So, to find the profit in one burrito, we would add -2.5+8, giving us an answer of 5.5. So, they earn 5 dollars and 50 cents each burrito and lose $2.50.
Now, we need to find the profit of 100 burritos
If one burrito is $5.50 in profit, then we take that amount and multiply it by 100. This is to make the illitsratution of selling 100 burritos. So, 5.50*100 would be 550! They would make $550 for 100 burritos, and lose 250 dollars on all of the burrito ingredients.
Answer:
The correct options are;
1) Write tan(x + y) as sin(x + y) over cos(x + y)
2) Use the sum identity for sine to rewrite the numerator
3) Use the sum identity for cosine to rewrite the denominator
4) Divide both the numerator and denominator by cos(x)·cos(y)
5) Simplify fractions by dividing out common factors or using the tangent quotient identity
Step-by-step explanation:
Given that the required identity is Tangent (x + y) = (tangent (x) + tangent (y))/(1 - tangent(x) × tangent (y)), we have;
tan(x + y) = sin(x + y)/(cos(x + y))
sin(x + y)/(cos(x + y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y))
(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y))
(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y)) = (tan(x) + tan(y))(1 - tan(x)·tan(y)
∴ tan(x + y) = (tan(x) + tan(y))(1 - tan(x)·tan(y)
Getting at least a 80% ( B average) is also good still very close to 90
3. We can see that
1+100=101
2+99=101
3+98=101
.................
and so on
From 1 to 100, there are 50 pairs that has the sum is 101
Z=101×50=5050
4. We can see that
1-2=-1
3-4=-1
5-6=-1
...........
and so on
There are 10 pairs that has sum is -1
Z= 10×(-1)=-10
