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sladkih [1.3K]
3 years ago
6

the odds of rolling a certain number on a single die is 1 chance in 6 rolls in the course of a game someone rolled 3 fives accor

ding to the odds how many times must that person have thrown the die?
Mathematics
2 answers:
monitta3 years ago
5 0

Answer:

18

Step-by-step explanation:

3 = 1/6 × n

n = 18

sergeinik [125]3 years ago
3 0

108 times. That is the probability of that happening.

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Help pls pls pls !!!!
kramer

Answer:

AAS

Step-by-step explanation:

I believe

6 0
3 years ago
What is the answer for <br> -16+x=-15
Sladkaya [172]

Answer:

x=1

Step-by-step explanation:

-16+x=-15

-16+x+16=-15+16   Add the terms to both sides of the equation.

After that you simplify.

5 0
3 years ago
Please help me with this 3x=9
fenix001 [56]

Answer:x = 3

Step-by-step explanation:

X =9/3

X=3

6 0
3 years ago
Read 2 more answers
write an expression for the sequence of operations described below. add s to t, add the result to r, then raise what you have to
Kobotan [32]

Answer:

(s+t+r)^7

Step-by-step explanation:

<u>Sequential Operations </u>

Mathematical operations can be done in sequence or in batches if they are of the same type. For example, we can add many terms in one single operation, but we cannot add and multiply in one go, because there are priorities when dealing with products and sums. Same happens with powers.

In our problem we are required to perform a sequence of operations like follows

Add s to t:

s+t

Add the result to r

s+t+r

Raise what you have to the 7th power

\boxed{(s+t+r)^7}

This is the final result

6 0
3 years ago
A manufacturer knows that 14% of the products it produces are defective. Find the probability that among 7 randomly selected pro
diamong [38]

Answer: 0.6521

Step-by-step explanation:

According to the Binomial distribution , the provability of getting x successes in n trials is given by :-

P(x)=^nC_xp^x(1-p)^{n-x} , where p=probability of getting success in each trial.

Let x denotes the number of defective products.

here , n=7 and p =0.14

Then, the probability that among 7 randomly selected products, at least one of them is defective= P(X ≥ 1) =1- P(X<1)

= 1- P(X=0)

=1-^7C_0(0.14)^0(1-0.14)^7

=1-(1(1)(0.86)^7\ \[\because ^nC_0=1]

=1-0.347927822217

=0.652072177783\approx0.6521

Hence, the probability that among 7 randomly selected products, at least one of them is defective is 0.6521 .

7 0
3 years ago
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