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3 years ago

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Mathematics

2 answers:

uranmaximum [27]3 years ago

7 0

Answer:

2.2%

Step-by-step explanation:

748/340=2.2

Black_prince [1.1K]3 years ago

5 0

Answer:

2.2%

Step-by-step explanation:

748 divided by 340 equals 2.2.

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For safety reasons, four different alarm systems were installed in the vault containing the safety deposit boxes at a Beverly Hi

larisa [96]

Answer: a) $(0.99)^4$

Step-by-step explanation:

Given : For safety reasons, four different alarm systems were installed in the vault containing the safety deposit boxes at a Beverly Hills bank.

Each of the four systems detects theft with a probability of .99 independently of the others .

Probability for independent events $(E_1 , E_2 , E_3 , ....., E_n)$ occurs together = $P(E_1)\times P(E_2)\times P(E_3)\ .....\times P(E_n)$ .

Then, the probability that when a theft occurs, all four systems will detect it

= (0.99) x (0.99) x (0.99) x (0.99)

$= (0.99)^4$

Hence, the probability that when a theft occurs, all four systems will detect it is $(0.99)^4$ .

Hence, the correct answer is a) $(0.99)^4$ .

5 0

3 years ago

3. Rewrite the expression as simply as you can:<br> 3x + 11y - 2x - 4y

vfiekz [6]

Answer:

x+7y

Step-by-step explanation:

First off, lets split the question into both x and y.

3x - 2x for the x

11y - 4y for the y

You can solve both of them to get x + 7y

3x - 2x = x

11y - 4y = 7y

Then, add them back up and get x + 7y

7 0

3 years ago

Read 2 more answers

How many tablespoons is one dose

allochka39001 [22]

Answer:

usually 2 depending on age

7 0

2 years ago

If we inscribe a circle such that it is touching all six corners of a regular hexagon of side 10 inches, what is the area of the

Brrunno [24]

Answer:

$\left(100\pi - 150\sqrt{3}\right)$ square inches.

Step-by-step explanation:

<h3>Area of the Inscribed Hexagon</h3>

Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be $10$ inches (same as the length of each side of the regular hexagon.)

Refer to the second attachment for one of these equilateral triangles.

Let segment $\sf CH$ be a height on side $\sf AB$ . Since this triangle is equilateral, the size of each internal angle will be $\sf 60^\circ$ . The length of segment

$\displaystyle 10\, \sin\left(60^\circ\right) = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3}$ .

The area (in square inches) of this equilateral triangle will be:

$\begin{aligned}&\frac{1}{2} \times \text{Base} \times\text{Height} \\ &= \frac{1}{2} \times 10 \times 5\sqrt{3}= 25\sqrt{3} \end{aligned}$ .

Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:

$\displaystyle 6 \times 25\sqrt{3} = 150\sqrt{3}$ .

<h3>Area of of the circle that is not covered</h3>

Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is $10$ inches, the radius of this circle will also be $10$ inches.

The area (in square inches) of a circle of radius $10$ inches is:

$\pi \times (\text{radius})^2 = \pi \times 10^2 = 100\pi$ .