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alexandr402 [8]
3 years ago
12

Can someone help I think it is -15.

Mathematics
1 answer:
Vikki [24]3 years ago
3 0
I believe that -15 is the answer
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Point H is between points L and S. LS = 14x -21 LH = 15 HS = 8x What is the length of segment LS?Immersive Reader (5 Points)
Fofino [41]

Answer:

LS = 63

Step-by-step explanation:

Given

LS = 14x - 21

LH = 15

HS = 8x

Required

Determine the length of LS

Since H is between L and S, then

LS = LH + HS

Substitute 14x - 21 for LS, 15 for LH and 8x for HS

14x - 21 = 15 + 8x

Collect Like Terms

14x - 8x = 21 + 15

6x = 36

Divide both sides by 6

x = 6

Substitute 6 for x in LS = 14x - 21

LS = 14(6) - 21

LS = 84 - 21

LS = 63

<em>Hence, the length of LS is 63 units</em>

7 0
3 years ago
HELP WILL MARK BRAINLIEST
Neporo4naja [7]

Answer:

ineedpointssorrry

Step-by-step explanation:

5 0
3 years ago
20 less than a number
agasfer [191]

Answer:

20 less than a number is equal to the number.

Step-by-step explanation:

8 0
3 years ago
The shark are fed three times a day during the morning feeding 2/15 of a ton. During the afternoon feeding the weight of fish fe
UNO [17]

Answer:

The shark are fed \frac16 \ ton of fish during the night.

Step-by-step explanation:

Given:

Weight of fish fed in the morning = \frac{2}{15}\ ton

Also Given:

During the afternoon feeding the weight of fish fed will be 1/15 of a ton more than the fish fed during the morning.

Weight of fish fed in the afternoon = \frac{2}{15}+\frac{1}{15}=\frac{2+1}{15}=\frac{3}{15}\ ton

Total fish fed in whole day = \frac12 \ ton

We need to find the Weight of fish fed in the night.

Solution:

Now we can say that;

Weight of fish fed in the night can be calculated by by subtracting Weight of fish fed in the morning and Weight of fish fed in the afternoon from Total fish fed in whole day .

framing in equation form we get;

Weight of fish fed in the night = \frac{1}{2}-\frac{2}{15}-\frac{3}{15}= \frac{1}{2}-(\frac{2}{15}+\frac{3}{15})=\frac{1}{2}-\frac{2+3}{15}= \frac{1}{2}-\frac{5}{15} = \frac{1}{2}-\frac{1}{3}

Now we will use LCM for making the denominator common we get;

Weight of fish fed in the night = \frac{1\times3}{2\times3}-\frac{1\times2}{3\times2} = \frac{3}{6}-\frac{2}{6}

Now denominator are common so we will solve the numerators.

Weight of fish fed in the night = \frac{3-2}{6}=\frac16 \ ton

Hence The shark are fed \frac16 \ ton of fish during the night.

3 0
3 years ago
Help I need it done now
Paha777 [63]
You need to submit the question you would like for us to answer.
6 0
3 years ago
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