1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tia_tia [17]
3 years ago
10

Becky is writing a coordinate proof to show that the diagonals of a parallelogram bisect each other. She starts by assigning coo

rdinates as given.
A parallelogram graphed on a coordinate plane. The parallelogram is labeled A B C D. The coordinates of vertex A are 0 comma 0. The coordinates of vertex B a comma 0. The coordinates of vertex C are not labeled. The coordinates of vertex D are b comma c. Diagonals A C and B D intersect at point E whose coordinates are not labeled.

Drag and drop the correct answer into each box to complete the proof.

The coordinates of point C are (Response area, c).

The coordinates of the midpoint of diagonal AC¯¯¯¯¯ are ​(a+b2, c2)​ .

The coordinates of the midpoint of diagonal BD¯¯¯¯¯ are (Response area, c2).

AC¯¯¯¯¯ and BD¯¯¯¯¯ intersect at point E with coordinates (a+b2,Response area)..

By the definition of midpoint, AE¯¯¯¯¯≅Response area and Response area≅DE¯¯¯¯¯.

Therefore, diagonals AC¯¯¯¯¯ and BD¯¯¯¯¯ bisect each other.

Give actual answer will give brainliest

Mathematics
2 answers:
Darya [45]3 years ago
8 0

Answer:

Read Under

Step-by-step explanation:

Just did the quiz. First one is "a + b"

Second spot put "a+b/2"

Third put "c/2"

Finally put "CE" and then "BE"

Fynjy0 [20]3 years ago
4 0

Answer:

1. a+b

2. a+b/2

3. c/2

4. CE

5. BE

Step-by-step explanation:

Hope this helps

You might be interested in
Please help 25 points!
tatuchka [14]

The answer is 2268pi ft^3

7 0
3 years ago
Read 2 more answers
Find the value of x. Round to the nearest degree.
lord [1]

<u><em>hii! how are you? hope you're having a good day! (: i wish you the best. <3 stay strong and stay safe!</em></u>

5 0
2 years ago
Chef Rita is cooking for a Sunday brunch. She knows that 222222 pancakes can feed 888 people. She is wondering how many people (
likoan [24]

Answer:

she can feed 2,220 people with 555555 pancakes.

Step-by-step explanation:

8 0
2 years ago
Write the resultant of the two vectors as an ordered pair. –6 5 and 6 –5
RideAnS [48]

Answer:

Resultant vector of two vectors is (0, 0).

Step-by-step explanation:

in this question two vectors having ordered pair (-6, 5) and (6, -5) have been given.

We can represent these vectors in the form of

\vec{A}=-6\hat{x}+5\hat{y}

and \vec{A'}=6\hat{x}+(-5)\hat{y}

Now the resultant of these vectors will be = A + A'

A + A' = \vec{A}=-6\hat{x}+5\hat{y} + \vec{A'}=6\hat{x}+(-5)\hat{y}

So the resultant vector = (0 + 0)

Therefore the resultant will be (0, 0)

8 0
3 years ago
Read 2 more answers
Match each vector operation with its resultant vector expressed as a linear combination of the unit vectors i and j.
Cloud [144]

Answer:

3u - 2v + w = 69i + 19j.

8u - 6v = 184i + 60j.

7v - 4w = -128i + 62j.

u - 5w = -9i + 37j.

Step-by-step explanation:

Note that there are multiple ways to denote a vector. For example, vector u can be written either in bold typeface "u" or with an arrow above it \vec{u}. This explanation uses both representations.

\displaystyle \vec{u} = \langle 11, 12\rangle =\left(\begin{array}{c}11 \\12\end{array}\right).

\displaystyle \vec{v} = \langle -16, 6\rangle= \left(\begin{array}{c}-16 \\6\end{array}\right).

\displaystyle \vec{w} = \langle 4, -5\rangle=\left(\begin{array}{c}4 \\-5\end{array}\right).

There are two components in each of the three vectors. For example, in vector u, the first component is 11 and the second is 12. When multiplying a vector with a constant, multiply each component by the constant. For example,

3\;\vec{v} = 3\;\left(\begin{array}{c}11 \\12\end{array}\right) = \left(\begin{array}{c}3\times 11 \\3 \times 12\end{array}\right) = \left(\begin{array}{c}33 \\36\end{array}\right).

So is the case when the constant is negative:

-2\;\vec{v} = (-2)\; \left(\begin{array}{c}-16 \\6\end{array}\right) =\left(\begin{array}{c}(-2) \times (-16) \\(-2)\times(-6)\end{array}\right) = \left(\begin{array}{c}32 \\12\end{array}\right).

When adding two vectors, add the corresponding components (this phrase comes from Wolfram Mathworld) of each vector. In other words, add the number on the same row to each other. For example, when adding 3u to (-2)v,

3\;\vec{u} + (-2)\;\vec{v} = \left(\begin{array}{c}33 \\36\end{array}\right) + \left(\begin{array}{c}32 \\12\end{array}\right) = \left(\begin{array}{c}33 + 32 \\36+12\end{array}\right) = \left(\begin{array}{c}65\\48\end{array}\right).

Apply the two rules for the four vector operations.

<h3>1.</h3>

\displaystyle \begin{aligned}3\;\vec{u} - 2\;\vec{v} + \vec{w} &= 3\;\left(\begin{array}{c}11 \\12\end{array}\right) + (-2)\;\left(\begin{array}{c}-16 \\6\end{array}\right) + \left(\begin{array}{c}4 \\-5\end{array}\right)\\&= \left(\begin{array}{c}3\times 11 + (-2)\times (-16) + 4\\ 3\times 12 + (-2)\times 6 + (-5) \end{array}\right)\\&=\left(\begin{array}{c}69\\19\end{array}\right) = \langle 69, 19\rangle\end{aligned}

Rewrite this vector as a linear combination of two unit vectors. The first component 69 will be the coefficient in front of the first unit vector, i. The second component 19 will be the coefficient in front of the second unit vector, j.

\displaystyle \left(\begin{array}{c}69\\19\end{array}\right) = \langle 69, 19\rangle = 69\;\vec{i} + 19\;\vec{j}.

<h3>2.</h3>

\displaystyle \begin{aligned}8\;\vec{u} - 6\;\vec{v} &= 8\;\left(\begin{array}{c}11\\12\end{array}\right) + (-6) \;\left(\begin{array}{c}-16\\6\end{array}\right)\\&=\left(\begin{array}{c}88+96\\96 - 36\end{array}\right)\\&= \left(\begin{array}{c}184\\60\end{array}\right)= \langle 184, 60\rangle\\&=184\;\vec{i} + 60\;\vec{j} \end{aligned}.

<h3>3.</h3>

\displaystyle \begin{aligned}7\;\vec{v} - 4\;\vec{w} &= 7\;\left(\begin{array}{c}-16\\6\end{array}\right) + (-4) \;\left(\begin{array}{c}4\\-5\end{array}\right)\\&=\left(\begin{array}{c}-112 - 16\\42+20\end{array}\right)\\&= \left(\begin{array}{c}-128\\62\end{array}\right)= \langle -128, 62\rangle\\&=-128\;\vec{i} + 62\;\vec{j} \end{aligned}.

<h3>4.</h3>

\displaystyle \begin{aligned}\;\vec{u} - 5\;\vec{w} &= \left(\begin{array}{c}11\\12\end{array}\right) + (-5) \;\left(\begin{array}{c}4\\-5\end{array}\right)\\&=\left(\begin{array}{c}11-20\\12+25\end{array}\right)\\&= \left(\begin{array}{c}-9\\37\end{array}\right)= \langle -9, 37\rangle\\&=-9\;\vec{i} + 37\;\vec{j} \end{aligned}.

7 0
3 years ago
Other questions:
  • (3x -1) + (2x+1) (x)
    14·1 answer
  • A company finds it can produce 5 heaters for $2000, while producing 15 heaters costs $4600. Express the cost, y, as a linear fun
    10·1 answer
  • 2. Evaluate the function (3pts each) f(x) = 2x2 -*+5 a) f(-2) b) f(2x) c) f(x-1) 3. Find the domain of the function. (5 pts each
    15·1 answer
  • Help me plz!!!!!!!!!!!!!
    5·1 answer
  • What do you used to find perimeter
    8·2 answers
  • Solve by elimination:<br> 3x + 4y = 0<br> 5x-3y = -58<br> (6, -8)<br> B (-6, -8)<br> C (-8, 6)
    8·1 answer
  • Which is greater 0.25 or 0.025
    13·1 answer
  • Write an expression for the perimeter of the triangle shown below
    14·2 answers
  • How to do this question
    5·1 answer
  • Which set of angle measures could be the measures of the interior angles of a triangle?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!