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tia_tia [17]
3 years ago
10

Becky is writing a coordinate proof to show that the diagonals of a parallelogram bisect each other. She starts by assigning coo

rdinates as given.
A parallelogram graphed on a coordinate plane. The parallelogram is labeled A B C D. The coordinates of vertex A are 0 comma 0. The coordinates of vertex B a comma 0. The coordinates of vertex C are not labeled. The coordinates of vertex D are b comma c. Diagonals A C and B D intersect at point E whose coordinates are not labeled.

Drag and drop the correct answer into each box to complete the proof.

The coordinates of point C are (Response area, c).

The coordinates of the midpoint of diagonal AC¯¯¯¯¯ are ​(a+b2, c2)​ .

The coordinates of the midpoint of diagonal BD¯¯¯¯¯ are (Response area, c2).

AC¯¯¯¯¯ and BD¯¯¯¯¯ intersect at point E with coordinates (a+b2,Response area)..

By the definition of midpoint, AE¯¯¯¯¯≅Response area and Response area≅DE¯¯¯¯¯.

Therefore, diagonals AC¯¯¯¯¯ and BD¯¯¯¯¯ bisect each other.

Give actual answer will give brainliest

Mathematics
2 answers:
Darya [45]3 years ago
8 0

Answer:

Read Under

Step-by-step explanation:

Just did the quiz. First one is "a + b"

Second spot put "a+b/2"

Third put "c/2"

Finally put "CE" and then "BE"

Fynjy0 [20]3 years ago
4 0

Answer:

1. a+b

2. a+b/2

3. c/2

4. CE

5. BE

Step-by-step explanation:

Hope this helps

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when you multiply a number by a value that's greater than 1, that number increases, for example 2 and then we multiply it like 2 * 3, clearly 2*3 is greater than 2.

now when you multiply a number  by a value that's lesser than 1, that number decreases, for example 2 and then we multiply it by something like 1/4, so 2 * 1/4 = 1/2, well, clearly 1/2 is smaller than 2, so 1/2 is a decreased value of 2.

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7 0
2 years ago
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