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3 years ago

Any polygon with two pairs of parallel opposite sides is a parallelogram. true or false?

2 answers:

3 0

This statement is false, it is not true that any polygon with two pairs of parallel opposite sides is considered to be a parallelogram for it is defined opposite than that. That is why the correct answer in the statement above is that it is false.

slamgirl [31]3 years ago

3 0

The given statement is

Any polygon with two pairs of parallel opposite sides is a parallelogram.

A parallelogram have 4 sides and a polygon can have 3,4,5,6,7,8, or any number of sides.

So it is not necessary that if opposite sides are parallel in a polygon than it is a parallelogram .

Therefore the given statement is false .

You might be interested in

Triangle ABC is formed by the vertices A(1,2,-1), B(-3,-6,2)and C(3,-2,0).

Vesnalui [34]

Answer:

Point D: $(0,-4, 1 )$

<em>d</em> = √41

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Pre-Calculus</u>

Midpoint Formula [3D]: $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}, \frac{z_1+z_2}{2} )$
Distance Formula [3D]: $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}$

Step-by-step explanation:

<u>Step 1: Define</u>

Point A(1, 2, -1)

Point B(-3, -6, 2)

Point C(3, -2, 0)

<u>Step 2: Find Point D</u>

Simply plug in your coordinates B and C into the midpoint formula to find midpoint

Substitute [MF]: $(\frac{-3+3}{2},\frac{-6-2}{2}, \frac{2+0}{2} )$
Add/Subtract: $(\frac{0}{2},\frac{-8}{2}, \frac{2}{2} )$
Divide: $(0,-4, 1 )$

<u>Step 3: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates A and D into the distance formula to find distance <em>d</em>

Substitute [DF]: $d = \sqrt{(0-1)^2+(-4-2)^2+(1+1)^2}$
Subtract/Add: $d = \sqrt{(-1)^2+(-6)^2+(2)^2}$
Exponents: $d = \sqrt{1+36+4}$
Add: $d = \sqrt{41}$

5 0

3 years ago

Smone answer ASAP please.

alina1380 [7]

The measure of the angle x is 117 degrees

<h3>Line geometry.</h3>

To determine the value of x in the given diagram, we will use the alternate angles theorem

The value of x is expressed as shown;

p + q= x

If the value of p = 51, then;

51 + q. = x

Determine the value of. q

q = 108 - 42

q = 66

Determine the value of x

x = 66 + 51

x = 117 degrees

Hence the measure of the angle x is 117 degrees

Learn more on angles here: brainly.com/question/25716982

#SPJ1

7 0

2 years ago

In the diagram, ABCDE is a regular pentagon.

RSB [31]

The shape ABCDE is a regular pentagon with five sides, such that the five sides are congruent

<h3>Part A: Calculate ∠BAE</h3>

The angle BAE is a vertex angle, and it is calculated using:

BAE = 180 * (n - 2)/n

Where n= 5; i.e. the number of sides.

This gives:

BAE = 180 * (5 - 2)/5

Evaluate

BAE = 108°

Hence, the measure of angle BAE is 108°

<h3>Part B: The name of the quadrilateral ABCD</h3>

When the vertices A and B are joined together, the shape becomes a trapezoid.

Hence, the name of the quadrilateral ABCD is a trapezoid.

<h3>Part C (i) Calculate ∠EDX</h3>

See attachment for the new figure.

From the attached figure, we have:

∠EDX + ∠EDC = 180° ---- the sum of angles on a straight line

Where:

∠EDC = ∠BAE = 108°

So, we have:

∠EDX + 108° = 180°

Subtract 108° from both sides

∠EDX = 72°

Hence, the measure of angle EDX is 72 degrees

<h3>Part C (ii) What type of quadrilateral is BDXE?</h3>

The quadrilateral BDXE is a parallelogram.

This is so because the opposite sides of BDXE are parallel, but not congruent