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3 years ago

Help me pls and dont guess

Mathematics

2 answers:

BARSIC [14]3 years ago

6 0

Answer:

Step-by-step explanation:

3 1/2 times -(4/5)

First multiply 3 1/2 and -(4/5)=2 4/5

Shkiper50 [21]3 years ago

4 0

Answer:

2 4/5

hope this helps!!

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Evaluate 8.1p + 7.9r when p=7 and r=8

Ivenika [448]

Answer:

119.9

Step-by-step explanation:

(8.1)(7)+(7.9)(8)

=119.9

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2 years ago

Complete the steps to find all zeroes of the function f(x) = x4 − 4x3 − 4x2 + 36x − 45. This function has roots.

xxTIMURxx [149]

Steps?

A graph shows zeros to be ±3. Factoring those out leaves the quadratic
(x-2)² +1
which has complex roots 2±i.

The function has roots -3, 3, 2-i, 2+i.

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3 years ago

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-3y = 2x - 9; x= -3, 0, 3

astraxan [27]

1.)-3y=2* -3-9
  -3y=-6-9
  -3y=-15
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-3*5=-15
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-3y=0-9
-3y=-9
y=3
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3 years ago

Factor 3x^3+6x^2+x+2 by grouping

bezimeni [28]

The answer for this question when grouping:

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3 years ago

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Find the solution of the differential equation that satisfies the given initial condition. y' tan x = 3a + y, y(π/3) = 3a, 0 &lt

Paladinen [302]

Answer:

$y(x)=4a\sqrt{3}* sin(x)-3a$

Step-by-step explanation:

We have a separable equation, first let's rewrite the equation as:

$\frac{dy(x)}{dx} =\frac{3a+y}{tan(x)}$

But:

$\frac{1}{tan(x)} =cot(x)$

So:

$\frac{dy(x)}{dx} =cot(x)*(3a+y)$

Multiplying both sides by dx and dividing both sides by 3a+y:

$\frac{dy}{3a+y} =cot(x)dx$

Integrating both sides:

$\int\ \frac{dy}{3a+y} =\int\cot(x) \, dx$

Evaluating the integrals:

$log(3a+y)=log(sin(x))+C_1$

Where C1 is an arbitrary constant.

Solving for y:

$y(x)=-3a+e^{C_1} sin(x)$

$e^{C_1} =constant$

So:

$y(x)=C_1*sin(x)-3a$

Finally, let's evaluate the initial condition in order to find C1:

$y(\frac{\pi}{3} )=3a=C_1*sin(\frac{\pi}{3})-3a\\ 3a=C_1*\frac{\sqrt{3} }{2} -3a$

Solving for C1:

$C_1=4a\sqrt{3}$

Therefore:

$y(x)=4a\sqrt{3}* sin(x)-3a$

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4 years ago