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3 years ago

Please help with number 9 and 10

Mathematics

1 answer:

cupoosta [38]3 years ago

3 0

Number 9 is 15 and number 10 is 30. There was 9 rectangles on number 9. 45 divided by 9 is 5, so each rectangle is worth 5. 3x5=15.

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Given the matrices: 1 2 A= 1 -1 2 1 1 B= 3 4 Calculate AB: C11 C12 [2.1] х 1 2 3 4 C21 C22 C11 = C12 = -2 C22 - C215 DONE

eduard

Answer:

$\:c_{11}=-2,\:\:\:c_{12}=-2$

$\:c_{21}=5,\:\:\:c_{22}=8$

Step-by-step explanation:

Given the matrices

$A=\begin{pmatrix}1&-1\\ 2&1\end{pmatrix}$

$B=\begin{pmatrix}1&2\\ \:3&4\end{pmatrix}$

Calculating AB:

$\begin{pmatrix}1&-1\\ \:\:2&1\end{pmatrix}\times \:\begin{pmatrix}1&2\\ \:\:3&4\end{pmatrix}=\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}$

Multiply the rows of the first matrix by the columns of the second matrix

$=\begin{pmatrix}1\cdot \:1+\left(-1\right)\cdot \:3&1\cdot \:2+\left(-1\right)\cdot \:4\\ 2\cdot \:1+1\cdot \:3&2\cdot \:2+1\cdot \:4\end{pmatrix}$

$=\begin{pmatrix}-2&-2\\ 5&8\end{pmatrix}$

Hence,

$\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}=\begin{pmatrix}-2&-2\\ \:5&8\end{pmatrix}$

Therefore,

$\:c_{11}=-2,\:\:\:c_{12}=-2$

$\:c_{21}=5,\:\:\:c_{22}=8$

5 0

3 years ago

Read 2 more answers

Simplify please help

aleksandr82 [10.1K]

Answer:

4√10xy/32y is the answer. (I think)

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2 years ago

The State Board of Education has $2,183 to buy new calculators. If each calculator costs $37, how many calculators can the board

Tema [17]

Answer:

Step-by-step explanation:

They could buy 59

You solve this by dividing the total amount of money ($2183) by the other amount ($37) which is 59

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3 years ago

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Valentin [98]

Answer:

-35

Step-by-step explanation:

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3 years ago

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What is the product of (2p+7)(3p+4p-3)

Alex

Answer:

The answer is C=6p3 + 29p2 + 22p – 21

Step-by-step explanation:

To calculate the product, we need to multiply each member of each multiplier:

(2p + 7)(3p2 + 4p – 3) = 2p · 3p² + 2p · 4p + 2p · -3 + 7 ·3p² + 7 · 4p + 7 · -3

= 6p³ + 8p² - 6p + 21p² + 28p - 21

= 6p³ + 8p² + 21p² + 28p - 6p -21

= 6p³ + 29p² + 22p - 21

Therefore, the product of (2p + 7)(3p2 + 4p – 3) is 6p³ + 29p² + 22p -21

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3 years ago

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