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3 years ago

Two similar pyramids have base edges 3 and 5. Find the following (use a colon between the numbers):

Mathematics

1 answer:

egoroff_w [7]3 years ago

5 0

Step-by-step explanation:

a) the ratio between their altitudes = 3:5

b) the ratio between their base areas = 9:25

c) the ratio between their lateral edges = 3:5

d) the ratio between their volumes = 27:125

e) the ratio between their lateral areas =9:25

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QRINC offered new employees a starting salary of $34,862 in 2013. What would a comparable starting salary have been in 2003?

Vlad1618 [11]

Complete Question

Table of Annual CPI values

2003-184.00

2004-188.90

2005-195.3

2006-201.6

2007-207.342

2008-215.303

2009-214.537

2010-218.056

2011-224.939

2012-229.594

2013-232.957

2014-236.736

QRINC offered new employees a starting salary of $34,862 in 2013. What would a comparable starting salary have been in 2003?

Answer:

$C=27535.5881128$

Step-by-step explanation:

From the question we are told that

CPI for 2003(index)=2003-184.00

CPI for 2013(index)=2013-232.957

Starting salary in 2013 at $34,862

Generally comparable starting salary C is given as

$C=\frac{starting salary}{CPI for 2013(index} *CPI for 2003(index)$

$C=\frac{34,862}{232.957} *184$

Therefore C the comparable starting salary is givrn to be

$C=27535.5881128$

$C=27536 appro$

8 0

3 years ago

For the given term, find the binomial raised to the power, whose expansion it came from: 15(5)^2 (-1/2 x) ^4

Elina [12.6K]

Answer:

C. $(5-\frac{1}{2})^6$

Step-by-step explanation:

Given

$15(5)^2(-\frac{1}{2})^4$

Required

Determine which binomial expansion it came from

The first step is to add the powers of he expression in brackets;

$Sum = 2 + 4$

$Sum = 6$

Each term of a binomial expansion are always of the form:

$(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......$

Where n = the sum above

$n = 6$

Compare $15(5)^2(-\frac{1}{2})^4$ to the above general form of binomial expansion

$(a+b)^n = ......+15(5)^2(-\frac{1}{2})^4+.......$

Substitute 6 for n

$(a+b)^6 = ......+15(5)^2(-\frac{1}{2})^4+.......$

[Next is to solve for a and b]

From the above expression, the power of (5) is 2

Express 2 as 6 - 4

$(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......$

By direct comparison of

$(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......$

and

$(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......$

We have;

$^nC_ra^{n-r}b^r= 15(5)^{6-4}(-\frac{1}{2})^4$

Further comparison gives

$^nC_r = 15$

$a^{n-r} =(5)^{6-4}$

$b^r= (-\frac{1}{2})^4$

[Solving for a]

By direct comparison of $a^{n-r} =(5)^{6-4}$

$a = 5$

$n = 6$

$r = 4$

[Solving for b]

By direct comparison of $b^r= (-\frac{1}{2})^4$

$r = 4$

$b = \frac{-1}{2}$

Substitute values for a, b, n and r in

$(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......$

$(5+\frac{-1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......$

Solve for $^6C_4$

$(5-\frac{1}{2})^6 = ......+ \frac{6!}{(6-4)!4!)}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ \frac{6!}{2!!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ \frac{6*5*4!}{2*1*!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ \frac{6*5}{2*1}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ \frac{30}{2}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+15*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+15(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+15(5)^2(\frac{-1}{2})^4+.......$

Check the list of options for the expression on the left hand side

The correct answer is $(5-\frac{1}{2})^6$

3 0

3 years ago

3x+4y=17 and slove for y

Llana [10]

Answer:

y=17/4 - 3x/4

Step-by-step explanation:

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3 years ago

What are the next three terms in the sequence? 1, 10, 2, 9, 3, ___, ___, ___

Basile [38]

I hope it helped for the question

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How much would you need to deposit in an account now in order to have 6,000 in the account in 8 years? Assume the account earns

liraira [26]

Answer:

Step-by-step explanation:

$1,000

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3 years ago