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3 years ago

8

You give tours on the Great Lakes and talk about points of interest. A lighthouse typically has 2 beacons that rotate together—b

ut not necessarily facing opposite directions. In that way, it can be a shorter time between the first and second flashes than between the second flash and the third flash (when the first beacon comes around for the second time). One way of identifying which lighthouse you are looking at is to find the ratio of the short time between flashes to the long time between flashes. If the beacons are set 120° apart along the rotation, as shown below, what is this ratio?

2 answers:

stiks02 [169]3 years ago

6 0

Answer:

i dont know

Step-by-step explanation:

Klio2033 [76]3 years ago

3 0

Answer:

great question

Step-by-step explanation:

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Lexi bulletin board is 40 centimeters wide,and her photos are 12 centimeters wide. What combinations of ribbons and photos will

Mrac [35]

Three would fit cause 3 times 12 is 36 and 4 times 12 is 48 which would be too big

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3 years ago

Please help x=10 evaluate f(x) a:24 b :16 C: no solution d :103

OLga [1]

Since $x=10$ we know our function is $f(x)=x^{2}+3$ .

To solve, substitute the given value:
$f(10)=10^{2}+3=100+3=103$

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3 years ago

Please help me figure this out :"D

PSYCHO15rus [73]

Hello! In order to solve the first problem, you need to know the properties of a rhombus.

Some basic rules that apply to the problem you should know are:

All sides of a rhombus are equal, however, a rhombus consists of two angles.
Opposite angles are congruent.
Adjacent angles are supplementary.
Diagonals intersect each other at 90 degrees.
Diagonals bisect the opposite interior angles.
All angles of a rhombus will always add up to 360 degrees.

To be congruent, line segments must be equal in length. The same rule applies to angles, they must be of equal measure.

This being said,

1. HT is congruent to MA

2. ST is congruent to MS

3. AMH is congruent to ATH

4. If angle MHT is 80 degrees, than angle MAT is 80 degrees as they are vertical (opposite) angles. This means they are always congruent.

5. If line MH = 9, then due to congruency AT must equal 9.

A square is 360 degrees. Every line is equal, every angle is equal.

There are four right angles in a square. A right angle equals 90 degrees.

Since every line has the same length, they are all congruent.

1. True

There are no angles less or more than 90 degrees in a perfect square.

2. False

KD and IN are not perpendicular since they do not intercept. They are parallel.

3. False

Every angle in a perfect square is 90 degrees.

4. True

You can draw out lines to get a better perception of KN and ID. They are congruent due to properties of a square.

5. True

4 0

3 years ago

there is a patch of lily pads on a lake every day the patch doubles in size if the patch has 200 lily pads how long ago did it h

AnnZ [28]

Answer:

600

Step-by-step explanation:

I

need

more

points

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3 years ago

Read 2 more answers

g Use this to find the equation of the tangent line to the parabola y = 2 x 2 − 7 x + 6 at the point ( 4 , 10 ) . The equation o

natali 33 [55]

Answer:

The tangent line to the given curve at the given point is $y=9x-26$ .

Step-by-step explanation:

To find the slope of the tangent line we to compute the derivative of $y=2x^2-7x+6$ and then evaluate it for $x=4$ .

$(y=2x^2-7x+6)'$ Differentiate the equation.

$(y)'=(2x^2-7x+6)'$ Differentiate both sides.

$y'=(2x^2)'-(7x)'+(6)'$ Sum/Difference rule applied: $(f(x)\pmg(x))'=f'(x)\pm g'(x)$

$y'=2(x^2)'-7(x)'+(6)'$ Constant multiple rule applied: $(cf)'=c(f)'$

$y'2(2x)-7(1)+(6)'$ Applied power rule: $(x^n)'=nx^{n-1}$

$y'=4x-7+0$ Simplifying and apply constant rule: $(c)'=0$

$y'=4x-7$ Simplify.

Evaluate y' for x=4:

$y'=4(4)-7$

$y'=16-7$

$y'=9$ is the slope of the tangent line.

Point slope form of a line is:

$y-y_1=m(x-x_1)$

where $m$ is the slope and $(x_1,y_1)$ is a point on the line.

Insert 9 for $m$ and (4,10) for $(x_1,y_1)$ :

$y-10=9(x-4)$

The intended form is $y=mx+b$ which means we are going need to distribute and solve for $y$ .

Distribute:

$y-10=9x-36$

Add 10 on both sides:

$y=9x-26$

The tangent line to the given curve at the given point is $y=9x-26$ .

------------Formal Definition of Derivative----------------

The following limit will give us the derivative of the function $f(x)=2x^2-7x+6$ at $x=4$ (the slope of the tangent line at $x=4$ ):

$\lim_{x \rightarrow 4}\frac{f(x)-f(4)}{x-4}$

$\lim_{x \rightarrow 4}\frac{2x^2-7x+6-10}{x-4}$ We are given f(4)=10.

$\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}$

Let's see if we can factor the top so we can cancel a pair of common factors from top and bottom to get rid of the x-4 on bottom:

$2x^2-7x-4=(x-4)(2x+1)$

Let's check this with FOIL:

First: $x(2x)=2x^2$

Outer: $x(1)=x$

Inner: $(-4)(2x)=-8x$

Last: $-4(1)=-4$

---------------------------------Add!

$2x^2-7x-4$

So the numerator and the denominator do contain a common factor.

This means we have this so far in the simplifying of the above limit:

$\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}$

$\lim_{x \rightarrow 4}\frac{(x-4)(2x+1)}{x-4}$

$\lim_{x \rightarrow 4}(2x+1)$

Now we get to replace x with 4 since we have no division by 0 to worry about:

2(4)+1=8+1=9.

6 0

4 years ago