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nadezda [96]
3 years ago
13

VERY VERY EASY WILL GIVE BRAINLEST!!!!!

Mathematics
1 answer:
Ludmilka [50]3 years ago
6 0

Answer:

2 units

Step-by-step explanation:

From the sides of the coordinate vertices PQ, you count how much coordinates on a graph it takes to get to one point as length.

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Wendy has $27 to buy seed for her birdfeeders. Each bag of seed costs $5.
Alekssandra [29.7K]

Answer:

5

Step-by-step explanation:

If Wendy has $27 to buy seeds, and each seed bag costs $5, then:

5 · 5 = 25

5 · 6 = 30

27<30

27>25

So, Wendy is able to buy 5 bags and remain with 2 dollars.

5 0
2 years ago
Read 2 more answers
In quadrilateral $ABCD$, we have $AB=3,$ $BC=6,$ $CD=4,$ and $DA=4$.
vampirchik [111]
The triangle inequality applies.

In order for ACD to be a triangle, the length of AC must lie between CD-DA=0 and CD+DA=8.

In order for ABD to be a triangle, the length of AC must lie between BC-AB=3 and BC+AB=9.

The values common to both these restrictions are numbers between 3 and 8. Assuming we don't want the diagonal to be coincident with any sides, its integer length will be one of ...
{4, 5, 6, 7}
8 0
3 years ago
6.8(6.7 – 7.2) – 2(4.6 + 1.2) = ???????
Gnesinka [82]

Answer:

6.8(6.7 – 7.2) – 2(4.6 + 1.2) =-15

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
There are 50 students going on a class trip. 35
iogann1982 [59]
The answer should be 74% probability

35/50+5/50-3/50= 37/50->74%
5 0
3 years ago
Find the probability that the mean annual preciptiation will be between 32 and 34 inches. variable is normally distributed
liq [111]
Supposing, for the sake of illustration, that the mean is 31.2 and the std. dev. is 1.9.

This probability can be calculated by finding z-scores and their corresponding areas under the std. normal curve.  
                                                                     34 in - 31.2 in
The area under this curve to the left of z = -------------------- = 1.47 (for 34 in)
                                                                           1.9
                                                                      32 in - 31.2 in
and that to the left of 32 in   is               z = ---------------------- = 0.421
                                                                             1.9

Know how to use a table of z-scores to find these two areas?  If not, let me know and I'll go over that with you.


My TI-83 calculator provided the following result:

normalcdf(32, 34, 31.2, 1.9) = 0.267  (answer to this sample problem)

5 0
3 years ago
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