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2 years ago

Question 6 of 6

Mathematics

1 answer:

Bezzdna [24]2 years ago

6 0

$\huge \boxed { \sf \: Answer}$

We have to use the formula:

$(ab) ^{n} = {a}^{n} {b}^{n}$

So,

$(5 \times 9) ^{12} \\ = {5}^{12} . 9^{12}$

Also, it will be

$45^{12}$

Hope you could understand.

If you have any query, feel free to ask.

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An engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 130 lb and

egoroff_w [7]

Answer:

a) $P(140$

$P(0.036$

b) $P(140< \bar X$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

$X \sim N(139,28.1)$

Where $\mu=139$ and $\sigma=28.1$

We are interested on this probability

$P(140$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(140$

And we can find this probability like this:

$P(0.036$

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.

$P(0.036$

Part b

For this case we select a sample size of n =32. Since the distribution for X is normal then the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=139, \frac{\sigma}{\sqrt{n}}=\frac{28.1}{\sqrt{32}}=4.97)$

And the new z score would be:

$Z=\frac{\bar X -\mu}{\sigma_{\bar x}}$

$P(140< \bar X$

5 0

3 years ago

PLEASE HELP:

Lady bird [3.3K]

Answer: (A) The image of JKL after a 90° counterclockwise about the origin is shown in figure 1. (B) The image of JKL after a reflection across the y-axis is shown in figure 2.

Explanation:

(A)

From the given figure it is noticed that the coordinate points are J(-4,1), K(-4,-2) and L(-3,-1).

If a shape rotate 90 degree counterclockwise about the origin, then,

$(x,y)\rightarrow (-y,x)$