Answer:
Distance between school and home = 105 miles.
Step-by-step explanation:
Let distance = D miles
Time to take walking/jogging, t1 = D/6 hours
Time by car, t2 = D/35 hours
Average time, t
= (t1+t2)/2
= D(1/6+1/35)
= (D/210)(35+6)
=41D/210 hours
Given t = t1-3 hours
41D/210 - D/6 = 3
Solve for D
41D/210 - 35D/210 = 3
(41-35)D/210 = 3
6D/210 = 3
D = 3*210/6 = 105 miles.
(Appreciate very much Diana's efforts to walk/job 105 miles to school, and we understand how lucky we are in most of Europe and North America)
There are 6+5 marbles.
Of those, 5 are red.
The chances of drawing a red marble are 5/11
Since you replace the marble you drew, the chances each draw remain 5/11
You cannot draw two red marbles without drawing a red marble on your first draw, so the odds of you making a second draw are 5/11. The odds of that also being red are 5/11… but we only care about that 5/11ths the time
5/11*5/11=25/121
A. 3 days a week: 12/80=0.15
B. MORE than 4 days a week: 28/80= 0.4625
C. at LEAST once a week: 0.8125
Correct.
Answer:
Step-by-step explanation:
Formula to be used is N=N0e^(kt)
N0 - amount of bacteria at time 0, which is 10g
t=2, 30g
30 = 10*e^(k*2)
3 = e^(2k)
2k = ln3
k = 0.5ln3
At t=6:
N = 10*e^(0.5ln3*6)
N = 10e^(3ln3)
N = 10e^ln27
N = 10*27 =270
So the amount of bacteria at t=6 is 270
<span>A) 2x - 4y = 10
B) 7x - 9y = 12
Multiplying equation A by -3.5
A) -7x +14y = -35 then adding B
B) </span><span><span>7x - 9y = 12</span>
5y = -23
y = -4.6
</span>
2x -4*-4.6 = 10
2x + 18.4 = 10
2x = -8.4
x = -4.2
It has one solution (-4.2, -4.6)
