If <span>ZW is an altitude of △XYZ, then m</span>∠ZWY = 90°
3a + 5 + 5a + 13 = 90
8a + 18 = 90
8a = 72
a = 72/8
a = 9
<span>m∠ZWT = 3a + 5 = 3*9 + 5 = 27 + 5 = 32</span>°
The frequency of the second class is 6.
Since the class width is 6 and the lower limit of the first class is 50, this means the first class goes from 50-55. This would put the second class at 56-61. There are 6 data points in this set that would go in the second class.
Answer:
non sampling error
Step-by-step explanation:
Sampling error in a statistical analysis arising from the unrepresentativeness of the sample taken.
Non Sampling error is a term used in statistics that refers to an error that occurs during data collection, causing the data to differ from the true values.
One tonne is equal to about 2,000lbs. So, if an adult African Elephant weighs 7 tonnes, that is about 14,000lbs. If you subtract 200lbs from 14,000, you get 13,800.
1 tonne = 2,000lbs
7 tonnes * 2,000lbs = 14,000lbs
14,000lbs - 200lbs = 13,800
So your answer would be an adult African Elephant is about 13,800lbs more than a new born elephant.
