<span>h<span>(t)</span>=<span>t<span>34</span></span>−3<span>t<span>14</span></span></span>
Note that the domain of h is <span>[0,∞]</span>.
By differentiating,
<span>h'<span>(t)</span>=<span>34</span><span>t<span>−<span>14</span></span></span>−<span>34</span><span>t<span>−<span>34</span></span></span></span>
by factoring out <span>34</span>,
<span>=<span>34</span><span>(<span>1<span>t<span>14</span></span></span>−<span>1<span>t<span>34</span></span></span>)</span></span>
by finding the common denominator,
<span>=<span>34</span><span><span><span>t<span>12</span></span>−1</span><span>t<span>34</span></span></span>=0</span>
<span>⇒<span>t<span>12</span></span>=1⇒t=1</span>
Since <span>h'<span>(0)</span></span> is undefined, <span>t=0</span> is also a critical number.
Hence, the critical numbers are <span>t=0,1</span>.
I hope that this was helpful.
45.5%, or 4.55, for 455/1000.
91/200
Step-by-step explanation:
f(x)=(x-5)(5x +2)=0
=> x=5 or, x=-2/5
smaller x = -2/5
larger x=5
First, start of by saying what the probability of getting a 4 is, which is 1/6.
Now, this means the probability of not getting a 4 is 1-(1/6)=(5/6), since the total probability is 1.
After doing this, you should think about what it means to only get 4 on the last trial, the 4th trial. It means that the probabilities of the 1st, 2nd, and 3rd trial were (5/6) each. The 4th trial had a probability of (1/6). So the probability would be calculated as following: (

=

. You can use a calculator or your computer to find out that the probability is 125/1296.
I hope this was helpful!
Well, if you look at the graph, when x = -1, y or f(x) = 4.
and when x = 2, y = 0.