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Furkat [3]
3 years ago
5

Use the table to complete the statements. The x-intercepts shown in the table are and . The y-intercept shown in the table is

Mathematics
2 answers:
Stolb23 [73]3 years ago
5 0

Answer:

The x-intercepts shown in the table are ✔ (–2, 0) and ✔ (2, 0).

The y-intercept shown in the table is ✔ (0, –4).

Step-by-step explanation:

sukhopar [10]3 years ago
4 0

Answer:

The x- intercepts shown in the table are (-2,0) and (2,0)

The y- intercept shown in the table is (0,-4)

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If corresponding angles are on parallel, then their measure is the same ____. always, sometimes, or never
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Step-by-step explanation:

Sometimes  hope that helps you and hope you pass : >

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Calculate the value of the following expressions
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13.04863882=13.05.Id k if this is what you search for?

Explanation:

3,6+2,5+,6.,2-,5=

3,6+2,5+1.228033638=

3,6+5.700169593=13.04863882=13.05

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8 0
3 years ago
A random sample of 100 teletype operators indicates that their salaries fluctuate quite a bit. The sample Standard deviation of
ELEN [110]

Answer:

\frac{(99)(10)^2}{123.225} \leq \sigma^2 \leq \frac{(99)(10)^2}{77.046}

80.341 \leq \sigma^2 \leq 128.495

Now we just take square root on both sides of the interval and we got:

8.963 \leq \sigma \leq 11.336

Step-by-step explanation:

Data given and notation

s=10 represent the sample standard deviation

\bar x represent the sample mean

n=100 the sample size

Confidence=90% or 0.90

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=100-1=99

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.05,99)" "=CHISQ.INV(0.95,99)". so for this case the critical values are:

\chi^2_{\alpha/2}=123.225

\chi^2_{1- \alpha/2}=77.046

And replacing into the formula for the interval we got:

\frac{(99)(10)^2}{123.225} \leq \sigma^2 \leq \frac{(99)(10)^2}{77.046}

80.341 \leq \sigma^2 \leq 128.495

Now we just take square root on both sides of the interval and we got:

8.963 \leq \sigma \leq 11.336

5 0
3 years ago
Plz help me I am struggling I will give you 15 pts
motikmotik

Answer: x = 2, y = 18

Step-by-step explanation:

Because if you go to 6 on the y axis and then keep going up the line until you meet with a number that's how you go get your answer. Hope this helped you!!

3 0
3 years ago
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