The 2-point form of the equation of a line can be written as ...
... y = (y2-y1)/(x2-x1)·(x -x1) +y1
For your points, this is ...
... y = (1-5)/(3-6)·(x -6) +5
... y = (4/3)(x -6) +5
It can also be written as
... y -5 = (4/3)(x -6)
Answer:
sorry abs
Step-by-step explanation:
The Equation in terms of m, m^2+7m+10=0
What is substituting in the equation ?
substituting means changing or replacing the values in the given equation.
Calculation:
Given equation is (x^2+3)^2+7x^2+21=-10
and m= X^2 + 3.
make the given equation in the form X^2 + 3,
now,
(x^2+3)^2+7x^2+21=-10
(x^2+3)^2+7(x^2+3)=-10
where,
X^2 + 3= m
after putting the value or replacing the values
we get, m^2+7m=-10
m^2+7m+10=0
the above equation is in the form of "m".
The Equation in terms of m, m^2+7m+10=0
Leran more about substitution here:
brainly.com/question/24094293
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Answer:
y = -2x + 8
Step-by-step explanation:
When two points are given, the equation of the line passing through the points is given by:
where: 
and 
are the two points passing through the line.
Here, 
and 
.
Substituting in the formula, we have:
⇒ 
⇒ y - 4 = -2x + 4
⇒ y = -2x + 8 is the required equation of the line.
