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jarptica [38.1K]

3 years ago

6

RJ and Ethan want to split a taco party pack from Taco Bell. The party pack costs $13.25. Together, RJ and Ethan. have $14.50. S

ince they have some money left over, they want to purchase two orders of cinnamon twists for an additional $2 (for both orders). Do they have enough money to purchase both the taco party pack and the cinnamon twists?

1 answer:

denpristay [2]3 years ago

7 0

No. If the cinnamon twists were purchased they would exceed $14.50.

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This is factoring quadratics with a leading coefficient: 5p to the 2 power - 52p + 20

Mashutka [201]

Answer:

(-5p + 2)(-p + 10)

Step-by-step explanation:

$5p^{2}$ -52p + 20

(-5p + 2)(-p + 10)

You can double check this by using the distributive property..

-5p * -p = -5p^2

2*-p = -2p

10*-5p = -50p

10*2 = 20

-5p^2 + -2p + -50p + 20

Now we combine like terms and simplify

-5p^2 -52p + 20

So, we are correct

4 0

3 years ago

A number line going from negative 10 to positive 10. Find the absolute value. |9| =

babymother [125]

Answer:

the answer is 9

Step-by-step explanation:

the absolute value of a number x takes x and makes it positive.

4 0

3 years ago

Find the absolute maximum and absolute minimum values of f on the given interval. f(t) = 2 cos(t) + sin(2t),[0, π/2].

castortr0y [4]

Answer:

The absolute maximum is $\frac{3\sqrt 3}2$ and the absolute minimum value is $0.$

Step-by-step explanation:

Differentiate of $f$ both sides w.r.t. $t$ ,

$f(t)=2 \cos t+\sin 2t$

$\Rightarrow f'(t)=-2\sin t+2\cos 2t$

Now take $f'(t)=0$

$\Rightarrow -2\sin t+2\cos 2t=0$

$\Rightarrow 2\cos 2t=2\sin t$

$\Rightarrow \cos 2t=\sin t$

$\Rightarrow 1-2\sin ^2t =\sin t \quad \quad [\because \cos 2t = 1-2\sin ^2t]$

$\Rightarrow 2\sin ^2t+\sin t-1=0$

$\Rightarrow 2\sin ^2t+2\sin t-\sin t-1=0$

$\Rightarrow 2\sin t(\sin t+1)-1(\sin t+1)=0$

$\Rightarrow (\sin t+1)(2\sin t-1)=0$

$\Rightarrow \sin t+1=0 \;\text{and}\; 2\sin t-1=0$

$\Rightarrow \sin t =-1 \;\text{and}\; \sin t =\frac 12$

In the interval $0\leq t\leq \frac {\pi}2$ , the answer to this problem is $\frac {\pi}6$

Now find the second derivative of $f(t)$ w.r.t. $t$ ,

$f''(t)=-2\cos t-4\sin 2t$

$\Rightarrow \left[f''(t)\right]_{t=\frac {\pi}6}=-2\times \frac {\sqrt 3}2-4\times \frac{\sqrt 3}2=-3\sqrt 3$

Thus, $f(t)$ is maximum at $t=\frac {\pi}6$ and minimum at $t=0$

$\left[f(t)\right]_{t=\frac {\pi}6}=2\times \frac {\sqrt 3}2+\frac{\sqrt 3}2=\frac{3\sqrt 3}2\;\text{and}\;\left[f(t)\right]_{t=\frac{\pi}2}= 2\times 0+0=0$

Hence, the absolute maximum is $\frac{3\sqrt 3}2$ and the absolute minimum value is $0$ .

7 0

3 years ago

Sati [7]

We would have to know the exact y coordinates at -3 and -1, then you would find the slope between these two points and that would be the average slope between -3 and 1

5 0

2 years ago

Help me with this please

Setler79 [48]

Answer: (4,2)

1 + 7 / 2 = 4

3 + 2 / 2 = 2

8 0

3 years ago

Read 2 more answers