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fiasKO [112]
3 years ago
15

If y varies inversely as x and y=3 when x=14, find x when y=6​

Mathematics
1 answer:
alukav5142 [94]3 years ago
3 0
X=7 What you can do is look at the first two values given, and make them x1 and y1. Then your next value here is y2.

So x1 is 14, and y1 is 3. y2 becomes 6. X2 is unknown.

Then make the formula: x1/y2 is equal to x2/y1
(You are setting two fractions equal to each other)

That makes 14/6=X/3. When we cross multiply, we find that x=7.
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Step-by-step explanation:

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3 years ago
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Which function is a quadratic function? y – 3x2 = 3(x2 + 5) + 1 y2 – 7x = 2(x2 + 6) + 7 y – 2x2 = 6(x3 + 5) – 4 y – 5x = 4(x + 5
Anna71 [15]

Answer:

Option A.

Step-by-step explanation:

The general form of a quadratic function is  

y=ax^2+bx+c

It means, power of y should be 1 and highest power of x should be 2.

In option A,

y-3x^2=3(x^2+5)+1

y-3x^2=3x^2+15+1

y=3x^2+16+3x^2

y=6x^2+16

It is a quadratic function.

In option B,

y^2-7x=2(x^2+6)+7

Here, power of y is 2. So, it is not be a quadratic function.

In option C,

y-2x^2=6(x^3+5)

Here, highest power of x is 3. So, it is not be a quadratic function.

In option D,

y-5x=4(x+5)+9

Here, highest power of x is 1. So, it is not be a quadratic function.

Therefore, the correct option is A.

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Step-by-step explanation:

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